将foreignKey小部件添加到django-import-export

时间:2014-09-04 16:25:14

标签: python django django-import-export

我正在尝试将数据导入到我的某个模型中,但它失败了,因为我正在尝试上传foreignKey Id,而不是导入导出创建的迭代数字。

models.py

from django.db import models
from import_export import resources


class School(models.Model):
    name = models.CharField(max_length=100)
    slug = models.CharField(max_length=100)
    school_id = models.IntegerField(unique=True)

class Sol(models.Model):
    school_id = models.ForeignKey(School, to_field='school_id')
    name = models.CharField(max_length = 100)
    Al1EOC = models.DecimalField(max_digits=5, decimal_places=2)
    AL2EOC = models.DecimalField(max_digits=5, decimal_places=2)

#Class for django-import-export
class SolResource(resources.ModelResource):
    class Meta:
        model = Sol

我的admin.py

from import_export.admin import ImportExportModelAdmin


class SolAdmin(ImportExportModelAdmin):
    list_display = ('name', 'school_id')
    resources_class = SolResource
    pass

admin.site.register(Sol, SolAdmin)

我的data.csv

id, name, school_id, Al1EOC, AL2EOC
,'Main st school', 1238008, 12.9, 14.9

当我从SOL模型导出数据时,我得到学校ID的迭代编号。我想要实际的学校ID - 持有foreignKey关系的那个。然后,我需要使用该foreignKey号上传数据。我知道ForeignKey小部件就是这样做的,但我不明白它是如何实现的。

3 个答案:

答案 0 :(得分:4)

文档中有ForeignKeyWidget。你可以在这里使用它。还有IntegerWidget和DecimalWidget。

from import_export.admin import ImportExportModelAdmin

class SolResource(resources.ModelResource):
    school_id = fields.Field(
        column_name='school_id',
        attribute='school_id',
        widget=ForeignKeyWidget(School, 'name'))

    class Meta:
        model = Sol

class SolAdmin(ImportExportModelAdmin):
    list_display = ('name', 'school_id')
    resources_class = SolResource

admin.site.register(Sol, SolAdmin)

这是一个有效的例子。希望它会有所帮助。

答案 1 :(得分:3)

我认为这会有所帮助:

class SolResource(resources.ModelResource):
    school_id = fields.Field()

    class Meta:
        # ...

    def dehydrate_school_id(self, sol):
        return sol.school_id.school_id # You can get all fields of related model. This is example.

答案 2 :(得分:3)

使用小工具很棒。

school_id = fields.Field(column_name='school_id', attribute='Sol', widget=widgets.ForeignKeyWidget(Sol, 'school_id'))