我正在尝试使用我运行程序的计算机的默认图像查看器打开一个打包在.jar文件中的图像文件。
我找到了许多关于如何使用InputStream访问打包在jar中的文件的答案,但是如何使用该InputStream打开这些文件?
InputStream imageStream = Test.class.getClass().getResourceAsStream("/test/DSC_6283.jpg");
我可以将其转换为Image
,ImageIcon
或BufferedImage
,但如何在默认图片查看器中进一步打开图片?
我的班级名称是'测试'我想要访问的图片是C:\Users\Pranav\Documents\NetBeansProjects\Test\src\test\DSC_6283.jpg
任何帮助都将不胜感激。
答案 0 :(得分:7)
纯java:
public static void main(String... args) throws IOException {
InputStream imageStream = Test.class.getClass().getResourceAsStream("/test/DSC_6283.jpg");
Path path = Files.createTempFile("DSC_6283", ".jpg");
try (FileOutputStream out = new FileOutputStream(path.toFile())) {
byte[] buffer = new byte[1024];
int len;
while ((len = imageStream.read(buffer)) != -1) {
out.write(buffer, 0, len);
}
} catch (Exception e) {
// TODO: handle exception
}
Desktop.getDesktop().open(path.toFile());
}
编辑:
byte[] buffer = new byte[1024]; //allocate an array of bytes to use as a buffer. 1024 bytes in this case
int len; //a variable to record the number of bytes actually read from the stream each loop
while ((len = imageStream.read(buffer)) != -1) { //InputStream.read(byte[]) reads bytes from the stream and places them into the buffer. It returns the number of bytes placed into the buffer, or -1 if there is nothing more to read. We store that result in len, and evaluate if we should stop looping (ie if the return is -1)
out.write(buffer, 0, len); //write to the output file, from the buffer, starting at position 0, through the number of bytes read
注意,这是样板文件。我从Easy way to write contents of a Java InputStream to an OutputStream
中偷了这个版本答案 1 :(得分:0)
Runtime.getRuntime().exec("cmd your_command_here_to_open_image");
这是Windows上cmd命令的链接:http://www.sevenforums.com/software/180378-where-windows-photo-viewer-default-location.html