Question

我希望能够在我的数据库的特定表中获得搜索结果的数量（让我们将其命名为wp_postmeta）。例如，如果我搜索确切的短语＆＃34;星期三（9月3日）＆＃34;，我希望能够通过php获得搜索结果的数量。

数据库示例

meta_id|post_id|meta_key           |meta_value

1      |123    |delivery-schedule  |Wednesday (3 Sep)
2      |124    |delivery-schedule  |Wednesday (3 Sep)
3      |125    |delivery-schedule  |Thursday (4 Sep)
4      |126    |delivery-schedule  |Friday (5 Sep)
5      |127    |delivery-schedule  |Wednesday (3 Sep)

所以在这种情况下，我应该得到3的结果。对不起，如果听起来太容易了。但我无法在任何地方找到答案。谢谢！

＆lt; - 这是我根据gihanmu建议尝试的 - ＆gt;

function test1() {
    $variable = "Wednesday(3 Sep)";
     $sql = "SELECT COUNT(*) FROM wp_postmeta WHERE meta_value='".$variable."'";
    //In your example $variable is Wednesday(3 Sep)
     $result=mysqli_query($connection,$sql);
     $count_array=mysqli_fetch_array($result);
     $exact_count=array_shift($count);
     echo $exact_count;
 }
add_action( 'woocommerce_before_order_notes', 'test1');

Answer 1

 $sql = "SELECT COUNT(*) FROM wp_postmeta WHERE meta_value='".$variable."'";
//In your example $variable is Wednesday(3 Sep)
 $result=mysqli_query($connection,$sql);
 $count_array=mysqli_fetch_array($result);
 $exact_count=array_shift($count);

$ count_array是一个数组，所以你必须使用array_shift（）函数拉出第一个元素以获得$ exact_count

Answer 2

SELECT COUNT(meta_id) FROM wp_postmeta WHERE meta_value = 'Wednesday (3 Sep)';

但是既然你正在使用PHP，那么你将需要mysqli;也许是这样的

$mysqli = new mysqli("localhost", "user", "password", "database");
$mydate = 'Wednesday (3 Sep)';  
$stmt = $mysqli->prepare("SELECT COUNT(meta_id) FROM wp_postmeta WHERE meta_value = ?");  
$stmt->bind_param('s', $mydate);  
$result = $stmt->execute();  
$stmt->bind_result($col1);  
while ($stmt->fetch()) { 
  echo "you have {$col1} rows matching $mydate\n";  
}

php获取数据库表的搜索结果号

2 个答案: