Question

我正在尝试为我的聊天应用程序处理我的ajax.php但由于某种原因我无法连接到我的数据库。我不明白为什么我收到此错误消息

注意：未定义的变量：第21行的dbOptions

捕获致命错误：传递给DB :: init（）的参数1必须是数组类型，给定null，在第21行调用并在第20行定义

这是我的代码

ajax.php

<?php
require "classes/DB.class.php";
require "classes/Chat.class.php";
require "classes/ChatBase.class.php";
require "classes/ChatLine.class.php";
require "classes/ChatUser.class.php";

session_name('webchat');
session_start();

if(get_magic_quotes_gpc()){

    // If magic quotes is enabled, strip the extra slashes
    array_walk_recursive($_GET,create_function('&$v,$k','$v = stripslashes($v);'));
    array_walk_recursive($_POST,create_function('&$v,$k','$v = stripslashes($v);'));
}

try{

    // Connecting to the database
    DB::init($dbOptions);

    $response = array();

    // Handling the supported actions:

    switch($_GET['action']){

        case 'login':
            $response = Chat::login($_POST['name'],$_POST['email']);
        break;

        case 'checkLogged':
            $response = Chat::checkLogged();
        break;

        case 'logout':
            $response = Chat::logout();
        break;

        case 'submitChat':
            $response = Chat::submitChat($_POST['chatText']);
        break;

        case 'getUsers':
            $response = Chat::getUsers();
        break;

        case 'getChats':
            $response = Chat::getChats($_GET['lastID']);
        break;

        default:
            throw new Exception('Wrong action');
    }

    echo json_encode($response);
}
catch(Exception $e){
    die(json_encode(array('error' => $e->getMessage())));
}
?>

DB.class.php

<?php
class DB {
    private static $instance;
    private $MySQLi;

    private function __construct(array $dbOptions){

        $this->MySQLi = @ new mysqli(   $dbOptions['localhost'],
                                        $dbOptions['root'],
                                        $dbOptions[''],
                                        $dbOptions['webchat'] );

        if (mysqli_connect_errno()) {
            throw new Exception('Database error.');
        }

        $this->MySQLi->set_charset("utf8");
    }

    public static function init(array $dbOptions){
        if(self::$instance instanceof self){
            return false;
        }

        self::$instance = new self($dbOptions);
    }

    public static function getMySQLiObject(){
        return self::$instance->MySQLi;
    }

    public static function query($q){
        return self::$instance->MySQLi->query($q);
    }

    public static function esc($str){
        return self::$instance->MySQLi->real_escape_string(htmlspecialchars($str));
    }
}
?>

我做错了吗？

Answer 1

您尚未设置$dbOptions有值。
您的数组键非常不合逻辑。我已经冒昧为你重命名。

加入ajax.php

$dbOptions = array();
$dbOptions['host'] = "localhost";
$dbOptions['user'] = "root";
$dbOptions['pass'] = "";
$dbOptions['database'] = "webchat";

// Connecting to the database
DB::init($dbOptions);

然后修改DB.class.php

private function __construct(array $dbOptions){

    $this->MySQLi = new mysqli($dbOptions['host'],
                                    $dbOptions['user'],
                                    $dbOptions['pass'],
                                    $dbOptions['database'] );

    if (mysqli_connect_errno()) {
        throw new Exception('Database error.');
    }

    $this->MySQLi->set_charset("utf8");
}

此外，永远不要在连接数据库时抑制错误。在异常逻辑中处理它们，如果失败则发回HTTP STATUS 500。

无法使用mysqli连接到数据库

1 个答案: