Question

在我当前的spring项目中，插入和更新事件在我的控制器中通过以下方法处理：

@RequestMapping(value="cadastra", method=RequestMethod.POST)
@ResponseBody
@ResponseStatus(HttpStatus.CREATED)
public String cadastra(@ModelAttribute("object") E object, BindingResult result, @RequestParam(value="file", required=false) MultipartFile file, @RequestParam(value="icone", required=false) MultipartFile icone, @RequestParam(value="screenshot", required=false) MultipartFile screenshot[]) throws Exception {
    if (serv.cadastra(object, file, icone, screenshot) != null)
        return "";
    else
        throw new Exception();
}

@RequestMapping(value="altera", method=RequestMethod.POST)
@ResponseBody
@ResponseStatus(HttpStatus.OK)
public String altera(@ModelAttribute("object") E object, BindingResult result, @RequestParam(value="file", required=false) MultipartFile file, @RequestParam(value="icone", required=false) MultipartFile icone, @RequestParam(value="screenshot", required=false) MultipartFile screenshot[]) throws Exception {
    if (serv.altera(object, file, icone, screenshot) != null)
        return "";
    else
        throw new Exception();
}

并通过此方法在服务类中：

@PreAuthorize("hasPermission(#user, 'cadastra_'+#this.this.name)")
@Transactional
public E cadastra(E e, MultipartFile file, MultipartFile icone, MultipartFile[] screenshot) {
    return dao.persist(e);
}

@PreAuthorize("hasPermission(#user, 'altera_'+#this.this.name)")
@Transactional
public E altera(E e, MultipartFile file, MultipartFile icone, MultipartFile[] screenshot) {
    return dao.merge(e);
}

我希望我的控制器返回视图，而不是空字符串，保存在数据库中的数据，以允许我使用此信息更新视图中的某些字段，即jquery。将使用此信息的代码之一是：

        $(".permissao").each(function(){
            var form = this;
            var type = $(form).data("type");
            $(form).ajaxForm(function(data){
                if(data == "") {
                    $(form).find(".alert-success").find(".alert-text").text("Solicitação efetuada com sucesso");
                    $(form).find(".alert-success").show();
                    if(type == "cadastra") {
                        console.log('cadastrado');
                        var id = 0;
                        var nome = "...";
                        var group = $('<div class="input-group" id="grupo_'+id+'">');
                        group.append('<span class="input-group-addon"></span>');
                        group.append('<input type="text" class="form-control" disabled="disabled" value="'+nome+'">');
                        group.append('<span class="input-group-btn"></span>');
                        $(".column").append(group);
                        add_input(id, 'plus');
                    }
                    if(type == "altera") {
                        console.log("alterado");
                        var id = 0;
                        $("#detail-"+id).empty();
                    }
                    if(type == "remove") {
                        console.log('removido');
                        var id = $(form).find("input[name='id']").val();
                        $("#grupo_"+id).remove();
                        $("#altera-"+id).remove();
                        $("#remove-"+id).remove();
                        $("#detail-"+id).remove();
                    }
                } else {
                    var $temp  = $('<div/>', {html:data});
                    $(form).find(".alert-danger").find(".alert-text").text( $temp.remove('head').html() );
                    $(form).find(".alert-danger").show();
                }
            });
        });

上面的变量id和nome应该接收对象中具有相同名称的字段的相应值。

任何人都可以指出我这样做的方向吗？

将持久对象的新状态返回到视图

0 个答案: