Question

       private string GenerateID()
        {


        }
        private void auto()
        {
            AdmissionNo.Text = "A-" + GenerateID();

        }

前缀为A，如下所示 A-0001 A-0002等。

Answer 1

您可以使用以下代码。

     `private string GenerateID() {
        int lastAddedId = 8;// get this value from database
        string demo = Convert.ToString(lastAddedId+1).PadLeft(4, '0');
        return demo;
        // it will return 0009

    }
    private void auto()
    {
        AdmissionNo.Text = "A-" + GenerateID();
        // here it will set the text as "A-0009"

    }

Answer 2

看看这个

public class Program
{
    private static int _globalSequence;

    static void Main(string[] args)
    {
        _globalSequence = 0;

        for (int i = 0; i < 10; i++)
        {
            Randomize(i);
            Console.WriteLine("----------------------------------------->");
        }


        Console.ReadLine();
    }

    static void Randomize(int seed)
    {
        Random r = new Random();
        if (_globalSequence == 0) _globalSequence = r.Next();

        Console.WriteLine("Random: {0}", _globalSequence);
        int localSequence = Interlocked.Increment(ref _globalSequence);

        Console.WriteLine("Increment: {0}, Output: {1}", _globalSequence, localSequence);
    }

}

Answer 3

恕我直言，它是否是Windows应用程序都不重要。我宁愿关心线程安全。因此，我将使用以下内容：

public sealed class Sequence
{
    private int value = 0;

    public Sequence(string prefix)
    {
        this.Prefix = prefix;
    }

    public string Prefix { get; }

    public int GetNextValue()
    {
        return System.Threading.Interlocked.Increment(ref this.value);
    }

    public string GetNextNumber()
    {
        return $"{this.Prefix}{this.GetNextValue():0000}";
    }
}

可以很容易地增强它以使用数字计数。因此，“ 0000”部分也可以动态指定。

如何在窗口应用程序中使用c＃生成序列号

3 个答案: