我正在尝试计算两列的余额。我尝试了很多方法。但没有运气。
例如:
我想得到这样的结果:
借记 信用 余额
===== ====== =======
125.00 0.00 125.00
236.00 0.00 361.00
0.00 100.00 261.00
我的代码
var filteredSales = (from av in db.AccountVouchers
join l in db.Ledgers on new {LedgerID = (Int32) av.LedgerID} equals new {LedgerID = l.LedgerID}
join sm in db.SalesMasters on av.VoucherNo equals sm.BillNo.ToString()
where (av.VoucherDate >= FromDate && av.VoucherDate <= ToDate && av.LedgerID == LedgerID)
group new {av, l, sm} by new
{
av.VoucherDate,
l.LedgerName,
av.VoucherType,
av.VoucherNo,
sm.REFNO,
av.Debit,
av.Credit,
av.Narration
}
into g
select new
{
g.Key.VoucherDate,
g.Key.LedgerName,
g.Key.VoucherType,
VoucherNo = (g.Key.VoucherType != "SALES" ? g.Key.REFNO : g.Key.VoucherNo),
//g.Key.VoucherNo,
g.Key.Debit,
g.Key.Credit,
g.Key.Narration,
dSum = g.Sum(s => s.av.Debit),
//Balance=g.Key.Debit-g.Key.Credit,
// TBal = int.Parse(TBal) + (g.Key.Debit != 0 ? TBal + g.Key.Debit : TBal - g.Key.Credit))
}).ToList();
答案 0 :(得分:1)
最后,我理解你的问题:
void Main()
{
var list=new List<test>
{
new test{ Debit=125, Credit=0},
new test{ Debit=236,Credit=0},
new test{ Debit=0, Credit=100},
};
if(list.Any())
{
var first = list.First();
first.Balance = first.Debit - first.Credit;
list.Aggregate((x,y)=>{ y.Balance = x.Balance + y.Debit - y.Credit; return y;});
}
list.Dump();
}
class test
{
public int Debit {get;set;}
public int Credit {get;set;}
public int Balance {get;set;}
}
答案 1 :(得分:0)
这显示了Tim的另一种语法示例。
void Main()
{
var list=new List<test>
{
new test{ Debit=125, Credit=0},
new test{ Debit=236,Credit=0},
new test{ Debit=0, Credit=100},
};
int balance = 0;
list = list.Select( i=> {
balance += i.Debit - i.Credit;
i.Balance = balance;
return i;
}).ToList();
list.Dump();
}
class test
{
public int Debit {get;set;}
public int Credit {get;set;}
public int Balance {get;set;}
}
这取自正在执行总计的答案here。正如评论中提到的那样,您应该小心,因为平衡值将关闭,您不会导致执行多次发生。使用ToList()可以解决这个问题。