Question

如果函数validateCustomForm()什么都不返回，则表示所有变量都已设置。我尝试使用empty()，但我想，因为函数中有一些东西总是返回false。

如何检查函数是否返回某些内容？

<?php

function validateCustomForm(){

$os0 = "";
$os1 = "5";
$os2 = "6";
$os3 = "5";
    if(!empty($os0)){
    //do nothing
    }else{
            $w = "width is missing";
    echo $w;
    }
    if(!empty($os1)){
    //do nothing
    }else{
            $h = "height is missing";
    echo $h;
    }
    if(!empty($os2)){
    //do nothing
    }else{
            $c = "color is missing";
    echo $c;
    }
    if(!empty($os3)){
    //do nothing
    }else{
            $q = "qty is missing";
    echo $q;
    }

    }//end function

$valid = validateCustomForm();

if(!empty($valid)){
echo "something is missing";
} else{
echo "all good";
}


?>

Answer 1

<?php

function validateCustomForm(){

    $os0 = "";
    $os1 = "5";
    $os2 = "6";
    $os3 = "5";

    $errors = array();

    if(empty($os0)){
        $errors[] = "width is missing";
    }
    if(empty($os1)){
        $errors[] = "height is missing";
    }
    if(empty($os2)){
        $errors[] = "color is missing";
    }
    if(empty($os3)){
        $errors[] = "qty is missing";
    }
    if(!empty($errors)) {
        return $errors;
    }
    return TRUE;
}//end function

$valid = validateCustomForm();

if($valid !== TRUE){
    echo "something is missing: ";
    echo implode(',' , $valid);
} else{
   echo "all good";
}


?>

Answer 2

你应该返回一些函数而不是echo。如下所示

<?php

function validateCustomForm(){

$os0 = "";
$os1 = "5";
$os2 = "6";
$os3 = "5";
$error = false;
    if(!empty($os0)){
    //do nothing
    }else{
            $w = "width is missing";
    $error = true;
    }
    if(!empty($os1)){
    //do nothing
    }else{
            $h = "height is missing";
     $error = true;
    }
    if(!empty($os2)){
    //do nothing
    }else{
            $c = "color is missing";
     $error = true;
    }
    if(!empty($os3)){
    //do nothing
    }else{
            $q = "qty is missing";
     $error = true;
    }
    return $error;
    }//end function

$valid = validateCustomForm();

if(!empty($valid)){
echo "something is missing";
} else{
echo "all good";
}


?>

检查函数是否返回了什么

2 个答案: