Question

我试图探索Spring的jdbctemplate的基础知识。我在一个简单的例子中遇到了麻烦：

public static void main(String[] args) throws Exception {
    JdbcDataSource dataSource = new JdbcDataSource();
    String url = "jdbc:h2:mem:test";
    dataSource.setURL(url);

    JdbcTemplate jdbcTemplate = new JdbcTemplate(dataSource);

    jdbcTemplate.execute("create table something (id int primary key, name varchar(100))");
    jdbcTemplate.execute("insert into something (id, name) values (1, 'Brian')");
}

触发：

Caused by: org.h2.jdbc.JdbcSQLException: Table "SOMETHING" not found; SQL statement:
insert into something (id, name) values (1, 'Brian') [42102-177]

如果我将该代码转换为使用原始JDBC api，它可以正常工作：

public static void main(String[] args) throws Exception {
    JdbcDataSource dataSource = new JdbcDataSource();
    String url = "jdbc:h2:mem:test";
    dataSource.setURL(url);

    try (Connection dbConnection = dataSource.getConnection()) {
        try (Statement statement = dbConnection.createStatement()) {
            statement.execute("create table something (id int primary key, name varchar(100))");
            statement.execute("insert into something (id, name) values (1, 'Brian')");

            try (ResultSet rs = statement.executeQuery("select id, name from something")) {
                while (rs.next()) {
                    System.out.println(String.format("got result. id=%d. name=%s", rs.getInt(1), rs.getString(2)));
                }
            }
        }
    }
}

如果重要，我的Gradle依赖项：

    compile 'org.springframework:spring-jdbc:4.0.6.RELEASE'
    compile 'com.h2database:h2:1.4.177'

Answer 1

请尝试使用update方法execute。

琐碎创建，插入jdbctemplate

1 个答案: