在二进制图像中查找最长的分支

时间:2014-09-03 21:37:22

标签: algorithm scala opencv search image-processing

我正在尝试找到骨架图像中最长的分支,并将最终图像显示为输出但是仍然存在于算法中。现在我能够找到一条线并在输出中绘制它。但我需要找到最长的线。这是我到目前为止所做的:

    var vect1= new scala.collection.mutable.ArrayBuffer[Point]()
    var p=new Point (0,0)
    var res = new Array[Byte](1)
    var u=skel.get(p.x.toInt,p.y.toInt,res)
    var value1: Int=0
    var value2: Int=0
    scala.util.control.Breaks.breakable {
            while((value1 < skel.rows ) ){
                    while ( (value2 < skel.cols )){
                             if (res(0) == -1) {
                                    p.x=(p.x.toInt)+value1
                                    p.y=(p.y.toInt)+value2
                                    scala.util.control.Breaks.break()
                              }
                    value2=value2+1
                    skel.get(value1,value2,res)
                    }
            value2=0
            value1=value1+1
            }
    }

    vect1 = traceLine(skel, p);
     //inside traceLine the algorithm makes a vector and looks for 8 neighbors around the point to find the next available point and make the vector then return the result and save it into vect1.

val output= new Mat (skel.rows, skel.cols, CvType.CV_8UC3,new Scalar(0, 0, 0))
val it = vect1.iterator //Iterator(vect1)
var vect3=new Array[Byte](3)
vect3(0)=0
vect3(1)=255.toByte
vect3(2)=0
vect1.foreach(p => output.put(p.x.toInt, p.y.toInt, vect3))

问题是我如何返回最长的分支?

0 个答案:

没有答案