Question

我在查询中使用了两个带有union的pivot操作符，我正在获取我想要的数据但我将第二个数据透视图中的数据作为新行，但我希望这些值作为表中的新列。我得到的数据是这样的：

Name    Ep  ER  FT  SQ       
Amir    2   9   3   2         
muzamil NULL    5   NULL     
roof    2   9   3   7        
Amir    0   9   3   1
muzamil NULL    5   NULL     
roof    2   7   3   7

前三行是第一个枢轴的输出，最后三行是第二个枢轴的输出。但我希望最后三行的值作为前三行的新列。

我希望数据输出如下：

Name    Ep  ER  FT  SQ          JB  CQ   LQ   YC
Amir    2   9   3   2            0   9   3   1
muzamil NULL    5   NULL        NULL 5  NULL NULL
roof    2   9   3   7             2  7   3    7

使用JB CQ LQ YC作为最后三行的新列，我的数据透视查询是这样的：

Declare @S  nvarchar(1024)
 Declare @Q nvarchar(Max)
set @S=''
Select   @S=@S+a.[Column] +',' from
(SELECT  distinct   ISNULL( dbo.tbSubjects.SubCode,'NoColumnName') as [Column] FROM         dbo.tbAttendance INNER JOIN
                      dbo.tbAttendanceMaster ON dbo.tbAttendance.MasterAID = dbo.tbAttendanceMaster.AtdID INNER JOIN
                      dbo.tbStudent ON dbo.tbAttendance.StID = dbo.tbStudent.StudentID INNER JOIN
                      dbo.tbSubjects ON dbo.tbAttendanceMaster.SubID = dbo.tbSubjects.SubID LEFT OUTER JOIN
                      dbo.tbSemester ON dbo.tbSubjects.SemID = dbo.tbSemester.SemID
                      ) as a

set @S=LEFT(@S,LEN(@S)-1)
 print @S
set @Q='select Name,'+@S+' from (SELECT  distinct tbStudent.Name,   dbo.tbSubjects.SubCode, dbo.fnTotalDays(dbo.tbAttendanceMaster.SubID, 
dbo.tbStudent.StudentID) AS Total 

FROM         dbo.tbAttendance INNER JOIN
                      dbo.tbAttendanceMaster ON dbo.tbAttendance.MasterAID = dbo.tbAttendanceMaster.AtdID INNER JOIN
                      dbo.tbStudent ON dbo.tbAttendance.StID = dbo.tbStudent.StudentID INNER JOIN
                      dbo.tbSubjects ON dbo.tbAttendanceMaster.SubID = dbo.tbSubjects.SubID LEFT OUTER JOIN
                      dbo.tbSemester ON dbo.tbSubjects.SemID = dbo.tbSemester.SemID ) sq
                      pivot(sum(Total)   for SubCode IN('+@S+') ) as pt
 union all
'
set @Q=@Q+'select Name,'+@S+' from (SELECT  distinct tbStudent.Name,   dbo.tbSubjects.SubCode, dbo.fnNoOfDays(dbo.tbAttendanceMaster.SubID, dbo.tbStudent.StudentID) AS Present

FROM         dbo.tbAttendance INNER JOIN
                      dbo.tbAttendanceMaster ON dbo.tbAttendance.MasterAID = dbo.tbAttendanceMaster.AtdID INNER JOIN
                      dbo.tbStudent ON dbo.tbAttendance.StID = dbo.tbStudent.StudentID INNER JOIN
                      dbo.tbSubjects ON dbo.tbAttendanceMaster.SubID = dbo.tbSubjects.SubID LEFT OUTER JOIN
                      dbo.tbSemester ON dbo.tbSubjects.SemID = dbo.tbSemester.SemID ) sq2
                      pivot(sum(Present)   for SubCode IN('+@S+') ) as pt2

'
 Execute sp_Executesql @Q
print @Q

想要改变多个枢轴结果

0 个答案: