Question

您好，我试图使用PHP将数据插入MSSQL。我已经多次尝试弄清楚问题可能是什么，但我似乎没有找到它。有什么东西没有得到正确或缺失吗？

 <?php
//pull form fields into php variables
$no = $_POST['no'];
$name= $_POST['name'];
$date = $_POST['date'];
$leave = $_POST['leave'];
$days= $_POST['days'];
$empno= $_POST['empno'];

//connect to sql
$dbc = mssql_connect('Server-PC','user','password','database')or die('Error connecting to
      the   SQL Server database.');

 // Input into staff database
  $query = "INSERT INTO dbo.[CAGD$Leave Plan] ([No_],[Employee No_],[Employee Name],
 [Leave Name],   [Start Date],[Leave Days],Satus) VALUES   
('$no','$name','$leave','$date','days','empno')";
$r esult = mssql_query($query,$dbc)or die('Error querying MSSQL database');

//close to sql
mssql_close($dbc);

echo $name . 'Your submission has been received<br />';
echo 'If you need change this request please contact your HR Manager<br />';
echo 'Thank you <br />';
echo 'HR Manager';
?>

我收到此错误消息：警告：mssql_query（）[function.mssql-query]：message：无效的对象名称'dbo.CAGD Plan'。
（严重级16）在第110行的C：\ xampp \ htdocs \ CAGD \ leave_request.php

Warning: mssql_query() [function.mssql-query]: Query failed in C:\xampp\htdocs  
\CAGD\leave_request.php on line 110
Error querying MSSQL database

Answer 1

首先指定数据库连接...

mssql_connect('Server-PC','user','password','database')
like -> "localhost","root","XXXX", "DBNAME"

然后查询

 $query = "INSERT INTO TABLENAME  (id,name) VALUES   
('$id','$name')";
$result = mssql_query($query,$dbc)

Answer 2

您可以使用SQLSRV驱动程序代替MSSQL驱动程序，然后尝试使用

<?php 
$serverName = "serverName";
$options = array(  "UID" => "sa",  "PWD" => "Password",  "Database" => "DBname");
$conn = sqlsrv_connect($serverName, $options);

if( $conn === false )
     {
     echo "Could not connect.\n";
     die( print_r( sqlsrv_errors(), true));
     }

$no = $_POST['no'];
$name= $_POST['name'];

$query = "INSERT INTO dbo.Test
        (No_,FirstName)
        VALUES(?, ?)";
$params1 = array($no,$name);                       
$result = sqlsrv_query($conn,$query,$params1);

sqlsrv_close($conn);
?>

这更有用，你可以在这里了解更多：

https://msdn.microsoft.com/en-us/library/cc626305(v=sql.105).aspx

Answer 3

嗯，在我看来，你在表格中有7个字段但只提交了6个值 - 你缺少第一列的值[No_]。此外，最后一列satus（我认为它应该是'status'）没有de []分隔符。返回的错误告诉您表的名称是错误的。是的变量名称在PHP中区分大小写，它应该是$ leave - 最好退出字符串并连接 - 类似于"bla bla".$leave."anything here with spaces or not"。

Answer 4

这应该是变量吗？

$query = "INSERT INTO dbo.[CAGD$Leave Plan] ([No_],[Employee No
                               ^^^^^^

如果是这样，那么它在您的代码中显然未定义，并且生成的查询字符串将包含dbo.[CAGD Plan]，而不是该变量中应该包含的任何值。如果$确实在您的表名中，那么它应该是CAGD\$Leave，因此$Leave不会被视为变量。

使用PHP将数据插入MSSQL DB

4 个答案: