如何从变量获取mysql查询传递值 并且它没有从变量传递值
here is my table structure
question
---------------------------------------
id qry name
---------------------------------------
1 select sal,price from rai
where id =$totno
2 select sal,price from sri
where id =$totno
-------------------------------------
这是我的编码部分
$totno=$_REQUEST['tno'];
$fno=$_REQUEST['sno'];
$fetqu=mysql_query(select * from testtmp where id='$fno');
while($rec=mysql_fetch_array($fetqu))
{
$qu=$rec['qry'];
}
echo $qu;
$tfet=mysql_query($qu);
while($rec=mysql_fetch_array($tfet))
{
$sal=$rec['sal'];
$price=$rec['price'];
}
这里没有从varible传递值我得到的错误就像
输出:
选择sal,其中id = $ totno的价格警告:mysql_fetch_row()期望参数1为资源,第11行的C:\ xampp \ htdocs \ rpt_pdf \ test.php中给出布尔值