Question

我正在使用boosts序列化函数来序列化并将数据保存到项目中的外部文件，然后再次读取它们。

我遇到的问题是，如果文件被读入（错误）而不是正确的格式，那么程序会崩溃（可能是预期的）。

如何识别文件格式错误并在程序崩溃前中断读取过程？

编辑：

我在我的read in函数中尝试了一个try catch构造，看起来像这样

int read_binary(file_in_out* object){

    std::ifstream ifs((*object).file.c_str());

    try
    {
        boost::archive::binary_iarchive ia(ifs);
        ia >> (*object).content;


    }
    catch (boost::archive::archive_exception& ex) 
    {
        std::cout << "An exception occurred. Exception Nr. "  << '\n';
        return 1;
    }
    catch (int e)
    {
        std::cout << "An exception occurred. Exception Nr. " << e << '\n';
        return 1;
    }

    return 0;

}

当文件与它试图读入的结构无关时，会捕获异常。但是，当我使用过时的版本时，它不会捕获异常并在'ia＆gt;＆gt;行崩溃（*对象）。内容;”有什么想法吗？

Answer 1

它不应该崩溃。如果是，请报告库开发人员的错误。

它应该引发异常。因此，您可以尝试捕获存档例外：

http://www.boost.org/doc/libs/1_36_0/libs/serialization/doc/exceptions.html

    unregistered_class,     // attempt to serialize a pointer of an
                            // an unregistered class
    invalid_signature,      // first line of archive does not contain
                            // expected string
    unsupported_version,    // archive created with library version subsequent
                            // to this one
    pointer_conflict        // an attempt has been made to directly serialize
                            // an object after having already serialized the same
                            // object through a pointer.  Were this permitted, 
                            // it the archive load would result in the creation
                            // of extraneous object.
    incompatible_native_format, // attempt to read native binary format
                            // on incompatible platform
    array_size_too_short,   // array being loaded doesn't fit in array allocated
    stream_error            // i/o error on stream
    invalid_class_name,     // class name greater than the maximum permitted.
                            // most likely a corrupted archive or an attempt
                            // to insert virus via buffer overrun method.
    unregistered_cast       // base - derived relationship not registered with 
                            // void_cast_register

另外，抓住std::exception&例如bad_alloc，range_error等。

c ++ boost serialization如何防止文件不正确崩溃

1 个答案: