我会直接举一个例子,我认为这更容易让人感到厌烦。 Music Cd有曲目。如何访问音乐Cd类中的“TrackInfo”矢量(XTrackInfo)数据? 我想打印甚至更改值,我不知道如何。 感谢
#include <iostream>
#include <vector>
#include <string>
#include <algorithm>
#include <iterator>
#include <numeric>
class XTrackInfo
{
std::string m_TrackName;
int m_Length;
public:
XTrackInfo() {}
XTrackInfo(std::string TrackName, int Length):
m_TrackName(std::move(TrackName)),
m_Length(Length)
{}
void SetTrackName(std::string TrackName) { m_TrackName = std::move(TrackName); }
void SetTrackLength(int Length) { m_Length = Length; }
const std::string& GetTrackName() const { return m_TrackName; }
int GetTrackLength() const { return m_Length; }
};
class XMusicCd
{
private:
std::string m_Author;
std::vector<XTrackInfo> m_TrackInfo;
public:
XMusicCd() {}
XMusicCd(std::string Author, std::vector<XTrackInfo> Tracks):
m_Author(std::move(Author)),
m_TrackInfo(std::move(Tracks))
{}
void SetAuthor(std::string Author) { m_Author = std::move(Author); }
const std::string& GetAuthor() const { return m_Author; }
const std::vector<XTrackInfo> GetTracks() const { return m_TrackInfo;}
int GetLength() const; // Left incomplete on purpose; you will implement it later
void AddTrack(XTrackInfo NewTrack){
m_TrackInfo.emplace_back(std::move(NewTrack));
}
};
void PrintCdContents(const XMusicCd& Cd)
{
std::cout << "Author : " << Cd.GetAuthor() << "\n";
std::cout << "\n" << std::endl;
std::cout << "Track Info" << std::endl;
//problems here :)
}
int main()
{
// You may not change this function
XMusicCd MyCd;
MyCd.SetAuthor("Hello World");
MyCd.AddTrack(XTrackInfo("This is a test", 100));
MyCd.AddTrack(XTrackInfo("This is a test 2", 200));
PrintCdContents(MyCd);
}
答案 0 :(得分:1)
使用迭代器:
std::vector<XTrackInfo> tracks = Cd.GetTracks();
for (std::vector<XTrackInfo>::const_iterator it = tracks.begin(); it != tracks.end(); ++it) {
std::cout << it->GetTrackName() << std::endl;
}
或索引:
std::vector<XTrackInfo> tracks = Cd.GetTracks();
for (unsigned i = 0; i < tracks.size(); ++i) {
std::cout << tracks.at(i).GetTrackName() << std::endl;
}