Question

以下是我的代码，它试图根据3个参数进行查询。但是以下查询适用于OR逻辑函数。有没有人知道AND逻辑功能如何。我按照文档中的说明尝试正常列出它们，但它总是返回一个空列表。

public class ResterauntList1 extends Activity {
    String rValue, cValue, lValue;
    ArrayAdapter<String> adapter;
    ProgressDialog mProgressDialog;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_resteraunt_list1);
        rValue = getIntent().getStringExtra("restrauntName");
        cValue = getIntent().getStringExtra("restrauntCuisine");
        lValue = getIntent().getStringExtra("restrauntLocation");
        populateList(rValue, cValue, lValue);
    }

    private void populateList(final String rValue, final String cValue,
            final String lValue) {

        ParseQueryAdapter.QueryFactory<ParseObject> factory = new ParseQueryAdapter.QueryFactory<ParseObject>() {

            @Override
            @SuppressWarnings({ "unchecked", "rawtypes" })
            public ParseQuery create() {
        ParseQuery<ParseObject> query = new ParseQuery("resdb");
        query.whereEqualTo("name", rValue);
        query.whereEqualTo("cuisine", cValue);
        query.whereEqualTo("area", lValue);
                return query;
            }
        };
        ParseQueryAdapter<ParseObject> adapter = new ParseQueryAdapter<ParseObject>(
                this, factory);
        adapter.setTextKey("name");
        adapter.addOnQueryLoadListener(new OnQueryLoadListener<ParseObject>() {

            @Override
            public void onLoading() {
                mProgressDialog = new ProgressDialog(ResterauntList1.this);
                mProgressDialog
                        .setTitle("Searching for Restaurants matching your search");
                mProgressDialog.setMessage("Loading...");
                mProgressDialog.setIndeterminate(false);
                mProgressDialog.show();
            }

            @Override
            public void onLoaded(List<ParseObject> objects, Exception e) {
                mProgressDialog.dismiss();
            }
        });

        final ListView listView = (ListView) findViewById(R.id.restListView1);
        listView.setAdapter(adapter);
        listView.setOnItemClickListener(new OnItemClickListener() {
            @Override
            public void onItemClick(AdapterView<?> parent, View view,
                    int position, long id) {
                ParseObject object = (ParseObject) listView
                        .getItemAtPosition(position);
                String Id = object.getObjectId();
                Intent i = new Intent(getApplicationContext(),
                        SingleRestraunt.class);
                i.putExtra("restId", Id);
                startActivity(i);

            }
        });
    }

不会返回任何错误，但它总是返回一个空的列表视图。有什么建议？正如额外的OR类型查询一样。

Answer 1

这应该是一个简单的解决方法。

ParseQuery<ParseObject> query = new ParseQuery("resdb");
           query.whereEqualTo("name", rValue);
           query.whereEqualTo("cuisine", cValue);
           query.whereEqualTo("area", lValue);

这将为您提供AND功能。

希望这有帮助！

如何在parsequery中执行AND

1 个答案: