python中的动态变量名

Question

我想用运行时间之前我不知道的字段名称过滤器调用查询...不确定如何构造变量名称......或者我可能累了。

field_name = funct()
locations = Locations.objects.filter(field_name__lte=arg1)

如果funct（）返回name将等于

locations = Locations.objects.filter(name__lte=arg1)

不知道怎么做......

Answer 1

您可以创建字典，设置参数并通过unpacking the dictionary as keyword arguments将其传递给函数：

field_name = funct()
params = {field_name + '__lte': arg1,       # field_name should still contain string
          'some_other_field_name': arg2}

locations = Locations.objects.filter(**params)

# is the same as (assuming field_name = 'some_name'):
# Locations.objects.filter(some_name__lte=arg1, some_other_field_name=arg2)