Question

<SHEET>
<books title ='title'>
<book label='1' page='1' intro='1'/>
<book label='2' page='2' intro='2'/>
<book label='3' page='3' intro='3'/>
</books>

<books title ='title'>
<book label='1' page='1' intro='1'/>
<book label='2' page='2' intro='2'/>
<book label='3' page='3' intro='3'/>
</books>


</SHEET>

所以我有这个代码，我用它来获取书籍项目中的属性。我使用这段代码：

[XmlRoot("SHEET")]
public class BookRoot
{
    private readonly List<Book> books = new List<Book>();
    [XmlArray("books"), XmlArrayItem("book")]
    public List<Book> Books { get { return books; } }
}
public class Book {
    [XmlAttribute("label")]
}

我还需要退出书籍属性，我该怎么做？

Answer 1

您要序列化的课程不尽如人意。考虑使用这样的：

[XmlRoot("SHEET")]
public class Sheet
{
    [XmlElementAttribute("books")]
    public sheetBooks[] books;

    public Sheet()
    {}
}

public class sheetBooks
{
    [XmlAttribute("title")]
    public string title;

    [XmlElementAttribute("book")]   
    public sheetBook book;

    public sheetBooks()
    {}
}

public class sheetBook
{
    [XmlAttribute("label")]
    public char label;

    [XmlAttribute("page")]
    public char page;

    [XmlAttribute("intro")]
    public char intro;

    public sheetBook()
    {}
}

标签，页面，介绍 - 它们总是低于10？在这种情况下char应该有效。否则，请检查string或int

的结果

序列化获取节点信息

1 个答案: