Question

我有一个C＃.Net脚本，可以将文件移动到目录，如果文件已经存在，则会向文件名添加增量。它在我的一个软件包中完美运行，但是我将其复制到另一个软件包中，它失败并显示以下错误消息：

    DTS SCript Task has encounter an exception in user code:
    Project name: ST_<blablabla>
    Exception has been thrown by the target of an invocation.

    at System.RuntimeMethodHandle.InvokeMethod(Object target,Object[] arguments,Signature si, Boolean constructor)
    at System.Reflection.RuntimeMethodInfo.UnsafeInvokeInternal(Object obj, Object[] paramters, Object[] arguments)
    at System.Reflection.RuntimeMethodInfo.Invoke(Object obj, BindingFlags invokeAttr, Binder binder, Object[] parameters, CultureInfo culture)
    at System.RuntimeType.InvokeMember(String name, BindingsFlags bindingFlags, Binder binder, Object target, Object[] providedArgs, ParameterModifier[] modifiers, CultureInfo culture, String[] namedParams)
    at Microsoft.SqlServer.Dts.Tasks.ScriptTask.VSTATaskScriptingEngine ExecuteScript()

这是实际的代码：

    public void Main()
    {
        // TODO: Add your code here

        string fileName = Dts.Variables["LoopFiles"].Value.ToString();

        System.IO.FileInfo file2 = new System.IO.FileInfo(Dts.Variables["FolderPath"].Value + fileName);

        int count = 1;
        string fullPath =Dts.Variables["FolderPath"].Value.ToString() +  Dts.Variables["LoopFiles"].Value.ToString();
        string fileNameOnly = Path.GetFileNameWithoutExtension(fullPath);
        string extension = Path.GetExtension(fullPath);
        string path = Path.GetDirectoryName(fullPath);
        string newFullPath = fullPath;

        while (File.Exists(newFullPath))
        {
            string tempFileName = string.Format("{0}({1})", fileNameOnly, count++);
            newFullPath = Path.Combine(path, tempFileName + extension);
        }

        DialogResult button3 = MessageBox.Show(file2.ToString());

        file2.MoveTo(newFullPath);

        DialogResult button5 = MessageBox.Show("Last Step");

        Dts.TaskResult = (int)ScriptResults.Success;
    }

作为一个注释，button3在运行时在例程中弹出，但在button5显示之前出现错误。任何关于为什么这么困难的信息都会有很大帮助。

谢谢！

Answer 1

所以我们必须看到异常 - 重写代码来捕获它：

try{
    file2.MoveTo(newFullPath);
    DialogResult button5 = MessageBox.Show("Last Step");
}catch(Exception ex){
    DialogResult button6 = MessageBox.Show(ex.ToString());
}

我认为根本不使用MessageBoxes - 使用控制台应用程序并向StdOut写消息要好得多

FileInfo.MoveTo在SSIS包中的C＃.Net脚本中生成错误

1 个答案: