我正在尝试获取一个快速类的属性列表。还有一个类似的问题here和here。除了某些类型之外我没有从class_copyPropertyList
返回所有内容。我到目前为止测试过的是Int?
和枚举。我在下面有一个示例课程,我正在尝试。
enum PKApiErrorCode: Int {
case None = 0
case InvalidSignature = 1
case MissingRequired = 2
case NotLoggedIn = 3
case InvalidApiKey = 4
case InvalidLogin = 5
case RegisterFailed = 6
}
class ApiError: Serializable {
let code: PKApiErrorCode?
let message: String?
let userMessage: String?
init(error: JSONDictionary) {
code = error["errorCode"] >>> { (object: JSON) -> PKApiErrorCode? in
if let c = object >>> JSONInt {
return PKApiErrorCode.fromRaw(c)
}
return nil
}
message = error["message"] >>> JSONString
userMessage = error["userMessage"] >>> JSONString
}
}
Serializable类(在https://gist.github.com/turowicz/e7746a9c035356f9483d的帮助下)
public class Serializable: NSObject, Printable {
override public var description: String {
return "\(self.toDictionary())"
}
}
extension Serializable {
public func toDictionary() -> NSDictionary {
var aClass : AnyClass? = self.dynamicType
var propertiesCount : CUnsignedInt = 0
let propertiesInAClass : UnsafeMutablePointer<objc_property_t> = class_copyPropertyList(aClass, &propertiesCount)
var propertiesDictionary : NSMutableDictionary = NSMutableDictionary()
for var i = 0; i < Int(propertiesCount); i++ {
var property = propertiesInAClass[i]
var propName = NSString(CString: property_getName(property), encoding: NSUTF8StringEncoding)
var propType = property_getAttributes(property)
var propValue : AnyObject! = self.valueForKey(propName);
if propValue is Serializable {
propertiesDictionary.setValue((propValue as Serializable).toDictionary(), forKey: propName)
} else if propValue is Array<Serializable> {
var subArray = Array<NSDictionary>()
for item in (propValue as Array<Serializable>) {
subArray.append(item.toDictionary())
}
propertiesDictionary.setValue(subArray, forKey: propName)
} else if propValue is NSData {
propertiesDictionary.setValue((propValue as NSData).base64EncodedStringWithOptions(nil), forKey: propName)
} else if propValue is Bool {
propertiesDictionary.setValue((propValue as Bool).boolValue, forKey: propName)
} else if propValue is NSDate {
var date = propValue as NSDate
let dateFormatter = NSDateFormatter()
dateFormatter.dateFormat = "Z"
var dateString = NSString(format: "/Date(%.0f000%@)/", date.timeIntervalSince1970, dateFormatter.stringFromDate(date))
propertiesDictionary.setValue(dateString, forKey: propName)
} else {
propertiesDictionary.setValue(propValue, forKey: propName)
}
}
return propertiesDictionary
}
public func toJSON() -> NSData! {
var dictionary = self.toDictionary()
var err: NSError?
return NSJSONSerialization.dataWithJSONObject(dictionary, options:NSJSONWritingOptions(0), error: &err)
}
public func toJSONString() -> NSString! {
return NSString(data: self.toJSON(), encoding: NSUTF8StringEncoding)
}
}
String似乎仅在Optionals为有效值时出现,并且code
永远不会出现在对象上(如果它是枚举或Int,除非Int具有默认值。
感谢您为获得课程的所有属性而获得的任何建议,无论他们是什么。
答案 0 :(得分:3)
我在苹果开发人员论坛上收到了有关此问题的回复:
&#34; class_copyPropertyList仅显示公开给Objective-C运行时的属性。 Objective-C不能表示Swift枚举或非引用类型的选项,因此这些属性不会暴露给Objective-C运行时。&#34;
因此,总而言之,目前无法使用此方法对JSON进行序列化。您可能必须考虑使用其他模式来完成此任务,例如为每个对象提供序列化任务,或者可能使用reflect() method将对象序列化为JSON。