PHP有一种简单的方法可以找出内置函数的源代码/内容吗?
比如说我想知道base64_decode()
对给定的编码base64字符串实际做了什么来将其转换为纯文本。我怎样才能做到这一点?
答案 0 :(得分:3)
您可以浏览PHP here
的源代码在您的情况下base64_decode
已实施here (PHP 5.6.0)
注意:此代码在C中,因为这就是PHP的编写内容。事实上,PHP的所有内置函数和扩展都是用C语言编写的。
PHPAPI unsigned char *php_base64_decode_ex(const unsigned char *str, int length, int *ret_length, zend_bool strict) /* {{{ */
{
const unsigned char *current = str;
int ch, i = 0, j = 0, k;
/* this sucks for threaded environments */
unsigned char *result;
result = (unsigned char *)safe_emalloc(length, 1, 1);
/* run through the whole string, converting as we go */
while ((ch = *current++) != '\0' && length-- > 0) {
if (ch == base64_pad) {
if (*current != '=' && ((i % 4) == 1 || (strict && length > 0))) {
if ((i % 4) != 1) {
while (isspace(*(++current))) {
continue;
}
if (*current == '\0') {
continue;
}
}
efree(result);
return NULL;
}
continue;
}
ch = base64_reverse_table[ch];
if ((!strict && ch < 0) || ch == -1) { /* a space or some other separator character, we simply skip over */
continue;
} else if (ch == -2) {
efree(result);
return NULL;
}
switch(i % 4) {
case 0:
result[j] = ch << 2;
break;
case 1:
result[j++] |= ch >> 4;
result[j] = (ch & 0x0f) << 4;
break;
case 2:
result[j++] |= ch >>2;
result[j] = (ch & 0x03) << 6;
break;
case 3:
result[j++] |= ch;
break;
}
i++;
}
k = j;
/* mop things up if we ended on a boundary */
if (ch == base64_pad) {
switch(i % 4) {
case 1:
efree(result);
return NULL;
case 2:
k++;
case 3:
result[k] = 0;
}
}
if(ret_length) {
*ret_length = j;
}
result[j] = '\0';
return result;
}