Question

以下是我们目前正在进行的网站设计/迁移（MAJOR HEADACHES）从直接的PHP / HTML网站到基于Drupal的网站的交易。我们有我们的家乡人（即我）在做事情，然后我们有设计人员，他们也有第三方做事。几个星期前，我使用旧网站的一些代码创建了一个视图 - drupal视图，它扫描目录并列出目录中有关我们员工报告的所有内容。从那时起我就没有碰过它，它一直很好，因为其他6页以同样的方式完成。星期四下午，该页面突然停止工作，只会呈现一个空白页面。我没碰过它，尽可能地告诉我其他人也没有。我将它与其他页面进行了比较，但我看不出有什么不妥。我错过了什么吗？或者这是Drupal问题吗？

<?php

$PHP_SELF = '/' . current_path();

$base = DRUPAL_ROOT . "/staff-reports";

$thisyear = date("Y");

# Strip out any HTML tags to eliminate cross-site scripting.
foreach ($_GET as $value) {
    $value = preg_replace("/<(.*?)>/","",$value);
}
# Then grab each GET value into a variable.
foreach ($_GET as $varname => $value) {
    $$varname = $value;
}

# If a year was not specified, use the current year by default.
if (!$year) {
    $year = $thisyear;
}

# List the year folders in the base directory (2001, 2002, et cetera).
if ($handle = opendir($base)) {
    while (false !== ($file = readdir($handle))) {
        // echo $file . '<br />';
        if( is_dir( $base . '/' . $file ) ){
            // echo $file . 'Is a directory <br />';
            if (preg_match("/\d\d\d\d/",$file)) {
                $years[count($years)] = $file;
            }
        }
    }

    closedir($handle);
    rsort($years);
}

# List the target year directory.
$reports = array();
$directory = $base . '/' . $year;
if ($handle = opendir($directory)) {
    while (false !== ($file = readdir($handle))) { 
        if (preg_match("/staff-report-\d\d\d\d-\d\d-\d\d\..../",$file)) {
            $reports[count($reports)] = $file;
        }
    }
    closedir($handle);
    if (count($reports)) {
        sort($reports);
    }
}

print "<table cellpadding=\"5\" border=\"1\" summary=\"Meetings\"><tr valign=\"top\">";

# Print the year index in the first column.
print "<td align=\"center\"><p><span class=\"bold\">Year index</span></p>\n";
for ($i = 0; $i < count($years); $i++) {
    if ($years[$i] == $year) {
        print "<b>";
    }
    print "<a href=\"$PHP_SELF?year=$years[$i]\">$years[$i]</a><br />\n";
    if ($years[$i] == $year) {
        print "</b>";
    }
}
print "</td>";

# Print the list of issues for the specified year in the other column.
print "<td align=\"center\"><p><span class=\"bold\">$year reports</span></p>\n";
if (count($reports)) {
#   print count($reports) . " issues<p>";
    for ($i = 0; $i < count($reports); $i++) {
        $y = substr($reports[$i],13,4);
        $m = substr($reports[$i],18,2);
        $d = substr($reports[$i],21,2);
#       print "<a href=\"/staff-reports/$year/$reports[$i]\">$m/$d/$y</a><br />\n";
        print "<a href=\"/staff-reports/$year/$reports[$i] \ "> ";
        print date("F j, Y", mktime(0,0,0,$m,$d,$y));
        print "</a><br />\n";
    }
} else {
    print "No reports";
}

print "<br />\n";

print "</td></tr></table>\n";

?>

<p>To view these documents, you need a PDF reader such as the <a
href="http://www.adobe.com/products/acrobat/readstep2.html">Adobe Reader</a>.</p>

<hr />

<?php

?>

Answer 1

基本PHP：" - 引用的字符串不能包含" - 引号，除非它们被转义：

    print "<a href=\"/staff-reports/$year/$reports[$i] \ "> ";
                                                       ^^

您的baskslash正在逃避空格，而不是"字符。

PHP突然停止了工作？

1 个答案: