我对Spring MVC比较陌生，并且熟悉Embedded Jetty。我们有一个现有的Spring MVC webapp，我可以编译成一个战争并放入Tomcat，它运行正常。但是我现在想在Embedded Jetty中运行它而不必将其放入Tomcat。
我已经按照本教程进行了操作，我发现这些教程很有用（只做了一些小改动）：
http://kielczewski.eu/2013/11/using-embedded-jetty-spring-mvc/
一切似乎都“差不多”，除了我的jsps的映射似乎不起作用。
这是我的主要课程：
public class EmbeddedJetty {
private static final int DEFAULT_PORT = 8080;
private static final String CONTEXT_PATH = "/";
private static final String CONFIG_LOCATION = "/WEB-INF/spring-servlet.xml";
private static final String MAPPING_URL = "/*";
public static void main(String[] args) throws Exception {
new EmbeddedJetty().startJetty(getPortFromArgs(args));
}
private static int getPortFromArgs(String[] args) {
if (args.length > 0) {
try {
return Integer.valueOf(args[0]);
} catch (NumberFormatException ignore) {
}
}
return DEFAULT_PORT;
}
private void startJetty(int port) throws Exception {
Server server = new Server(port);
WebApplicationContext context = getContext();
ServletContextHandler servletContextHandler = getServletContextHandler(context);
server.setHandler(servletContextHandler);
server.start();
server.join();
ResourceHandlerRegistry rhr = new ResourceHandlerRegistry(context, servletContextHandler.getServletContext());
rhr.addResourceHandler("images/**").addResourceLocations("images/");
rhr.addResourceHandler("jsp/**").addResourceLocations("jsp/");
rhr.addResourceHandler("css/**").addResourceLocations("css/");
}
private static ServletContextHandler getServletContextHandler(WebApplicationContext context) throws IOException {
ServletContextHandler contextHandler = new ServletContextHandler();
contextHandler.setErrorHandler(null);
contextHandler.setContextPath(CONTEXT_PATH);
DispatcherServlet dispatcherServlet = new DispatcherServlet(context);
ServletHolder servletHolder = new ServletHolder(dispatcherServlet);
contextHandler.addServlet(servletHolder, MAPPING_URL);
contextHandler.addEventListener(new ContextLoaderListener(context));
contextHandler.setResourceBase(new ClassPathResource("webapp").getURI().toString());
return contextHandler;
}
private static WebApplicationContext getContext() {
XmlWebApplicationContext context = new XmlWebApplicationContext();
context.setConfigLocation(CONFIG_LOCATION);
return context;
}
}
这是我的web.xml：
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
id="WebApp_ID" version="2.5">
<!-- Welcome file -->
<display-name>USER Administration</display-name>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
<!-- This is the servlet that will route to the correct Controller based on annotations -->
<servlet>
<servlet-name>spring</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<!--Map non-resource URLs to the DispatcherServlet -->
<servlet-mapping>
<servlet-name>spring</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<!-- Allow access to the resources -->
<servlet-mapping>
<servlet-name>default</servlet-name>
<url-pattern>*.png</url-pattern>
<url-pattern>*.js</url-pattern>
<url-pattern>*.css</url-pattern>
</servlet-mapping>
</web-app>
这是我的spring-servlet.xml（相关部分 - 我认为）：
<!-- This is the base package(s) for where spring should scan for @Component, @Service, @Controller, etc -->
<context:component-scan base-package="com.my.user.admin" />
<!-- A resolver for the returned ModelAndView objects and other strings, this tells it to append .jsp and look in the /WEB-INF/jsp/ for it -->
<bean id="viewResolver" class="org.springframework.web.servlet.view.UrlBasedViewResolver">
<property name="viewClass" value="org.springframework.web.servlet.view.JstlView" />
<property name="prefix" value="/jsp/" />
<property name="suffix" value=".jsp" />
</bean>
<bean id="multipartResolver" class="org.springframework.web.multipart.commons.CommonsMultipartResolver">
<!-- one of the properties available; the maximum file size in bytes -->
<property name="maxUploadSize" value="100000"/>
</bean>
<!-- loads in property files for use in this config -->
<bean id="propertyConfigurer"
class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
<property name="locations">
<list>
<value>classpath:Frameworks/hibernate.properties</value>
<value>classpath:Frameworks/activemq.properties</value>
</list>
</property>
</bean>
<!-- Hibernate 3 session factory used for session management -->
<bean id="sessionFactory" class="org.springframework.orm.hibernate3.LocalSessionFactoryBean">
<property name="configLocation" value="classpath:${hibernate.config.location}" />
</bean>
然后我使用maven shade插件构建它，并使用以下命令运行它：
java -classpath c:\dev\customclasspath;target\user-admin.jar com.admin.main.EmbeddedJetty
它启动了，并且在日志中看起来都很好，我看到很多行将Java类加载到URL上：
Mapped URL path [/modifyUser] onto handler 'menuController
Mapped URL path [/modifyUser.*] onto handler 'menuControll
Mapped URL path [/modifyUser/] onto handler 'menuControlle
Mapped URL path [/addUser] onto handler 'menuController'
Mapped URL path [/addUser.*] onto handler 'menuController'
Mapped URL path [/addUser/] onto handler 'menuController'
但是当我尝试在“localhost：8080”加载我的应用程序时，我得到一个“Not Found - Powered by Jetty”页面，在日志中我看到以下消息：
No mapping found for HTTP request with URI [/] in DispatcherServlet with name 'org.springframework.web.servlet.DispatcherServlet-6910fe28'
我做错了什么？在我的jar文件中，我可以看到文件/webapp/index.jsp，所以我认为可能是这样，但如果我做“localhost：8080 / webapp /”也不起作用。我不知道现在要改变什么，任何帮助都将不胜感激！
EDIT1
我认为这个问题是因为它实际上并没有加载我的web.xml文件（我定义了servlet-mappings），因为我创建了Jetty Context作为spring上下文，而不是'WebAppContext'。但是，我需要spring-servlet.xml文件，因为它包含我的所有控制器。如何加载它们？
答案 0 :(得分：0)
只有在没有URI的servlet映射时才使用欢迎文件。在你的情况下有一个：
<servlet-mapping>
<servlet-name>spring</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
除了.png / .js / .css外，它处理任何。