Question

我想用黑色和一些不透明度来遮挡原始图像。想要使原始图像更暗一点。我使用编写此代码，但它不起作用：

$image = new Imagick("test.jpg");

$drawblacklayer = new ImagickDraw();
$drawblacklayer->setFillColor('black');
$drawblacklayer->setFillOpacity(0.8);
$coordinate = array( array( 'x' => 0, 'y' => 0 ), array( 'x' => 200, 'y' => 200 ) ); // seems need to use the original size of $image, but it's testing

$drawblacklayer->polygon($coordinate);

$image->drawImage($drawblacklayer);

header('Content-type: image/png');
echo $image;

Answer 1

如果你期望一个黑暗的方格，你的$coordinate数组将需要定义所有点。

$coordinate = array( 
    array( 'x' =>   0, 'y' =>   0 ), // Top-Left
    array( 'x' => 200, 'y' =>   0 ), // Top-Right
    array( 'x' => 200, 'y' => 200 ), // Bottom-Right
    array( 'x' =>   0, 'y' => 200 ), // Bottom-Left

);
$drawblacklayer->polygon($coordinate);

或使用ImagickDraw::rectangle方法。

$drawblacklayer->rectangle( 0, 0, 200, 200 );

php - imagemagick模糊图像与黑色

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