我是nodejs和mongoose的新手。 我有一个从2009年到现在的数据库,想要计算每个月的数据, 并返回为json数组。慢速异步回调导致所有日期为2014年8月1日
实现这个的正确方法是什么?
var dbURL = 'mongodb://localhost/database';
var db = require('mongoose').connect(dbURL);
var c_db = require('./models/models.js').c_db;
var start_date = new Date(2009,0,1);
end_date = new Date(2014,8,1),
next_date = new Date();
var test_json=[];
var total_months = (end_date.getFullYear() - start_date.getFullYear())*12 + (end_date.getMonth() - start_date.getMonth());
var next_date = start_date;
for(var i=0;i<total_months;i++){
var firstDay = new Date(next_date.getFullYear(), next_date.getMonth(), 1);
var lastDay = new Date(next_date.getFullYear(), next_date.getMonth() + 1, 0);
next_date.setDate(lastDay.getDate()+1);
c_db.count({'shipdate':{'$gte':new Date(firstDay),'$lte':new Date(lastDay)}},function(err,query){
var item = {
"Date": firstDay,
"Count": query
}
test_json.push(item);
});
}
setTimeout(function(){
console.log(test_json);
},5000);
答案 0 :(得分:1)
使用异步回调编写javascript时要小心。您要做的是在当前异步完成时继续循环中的下一个项目。您可以使用&#34; async&#34;模块:https://github.com/caolan/async
var async = require("async");
var dbURL = 'mongodb://localhost/database';
var db = require('mongoose').connect(dbURL);
var c_db = require('./models/models.js').c_db;
var start_date = new Date(2009,0,1);
end_date = new Date(2014,8,1),
next_date = new Date();
var test_json=[];
var total_months = (end_date.getFullYear() - start_date.getFullYear())*12 + (end_date.getMonth() - start_date.getMonth());
var next_date = start_date;
async.timesSeries(total_months, function(n, next) {
var firstDay = new Date(next_date.getFullYear(), next_date.getMonth(), 1);
var lastDay = new Date(next_date.getFullYear(), next_date.getMonth() + 1, 0);
next_date.setDate(lastDay.getDate()+1);
c_db.count({'shipdate':{'$gte':new Date(firstDay),'$lte':new Date(lastDay)}},function(err,query){
var item = {
"Date": firstDay,
"Count": query
}
test_json.push(item);
next();
});
}, function(e) {
console.log(test_json);
});