我没有运气试图将作为GET传递的数组中的值与数据库记录集do / while循环中的值进行比较。我试图勾选一个复选框,如果GET数组中的任何值与记录集ID匹配。如果您在URL中仅使用一个兴趣ID而不使用逗号,则它可以正常工作。谢谢。
我的网址是: interestSearch.php?interests = 3(这个有效) interestSearch.php?interests = 3,8(不起作用)
<? require('db.php');
mysql_select_db($database_data);
$query_allInterests = "SELECT * FROM interests";
$allInterests = mysql_query($query_allInterests, $data) or die(mysql_error());
$row_allInterests = mysql_fetch_assoc($allInterests);
$totalRows_allInterests = mysql_num_rows($allInterests);
?>
<form method="get">
<? do { ?>
<input <?
if(isset($_GET['interests']) && $_GET['interests'] != "") {
$theCounter = 0;
$theArray = array($_GET['interests']);
foreach ($theArray as $value) {
// if ($value == $row_allInterests['id']) {$theCounter++;}
if (in_array($row_allInterests['id'], $theArray)) {$theCounter++;}
}
if($theCounter > 0){echo "checked";}
}
?> name="<? echo $row_allInterests['id']; ?>" class="doCheck" type="checkbox" id="<? echo $row_allInterests['id']; ?>" value="<? echo $row_allInterests['id']; ?>" /> <? echo $row_allInterests['interest']; ?><br />
<? } while ($row_allInterests = mysql_fetch_assoc($allInterests)); ?>
</form>
答案 0 :(得分:0)
而不是
$theArray = array($_GET['interests']);
使用
$theArray = explode( ',', $_GET['interests']);