给定一些任意SQL我想获取返回列的数据类型。该语句可能会连接许多表,视图,TVF等。我知道我可以根据查询创建一个视图并从中获取数据类型,希望有更快的方法。只是认为我能够想到的是编写.net实用程序来运行SQL并检查结果,想知道是否有TSQL答案。
即
给出(不是真正的表只是一个例子)
SELECT p.Name AS PersonName, p.Age, a.Account as AccountName
FROM Person as p
LEFT JOIN Account as a
ON p.Id = a.OwnerId
我想要像
这样的东西PersonName :( nvarchar(255),not null)
年龄:( smallInt,not null)
等...
答案 0 :(得分:1)
/*you may have to alias some columns if they are not unique*/
/*EDIT: added fix for 2byte nchar/nvarchar */
SELECT top (1) /*<your query columns here>*/
INTO #tmp99
/*<rest of your query here>*/
SELECT 'CREATE TABLE [tablename](' UNION ALL
SELECT CASE WHEN ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) = 1 THEN '' ELSE ',' END
+ CHAR(13) + '[' + c.name + '] [' + t.name + ']'
+ CASE WHEN c.system_type_id IN (165,167,173,175)
THEN CASE WHEN c.max_length <> -1
THEN '(' + CAST(c.max_length AS varchar(7)) + ')'
ELSE '(max)'
END
WHEN c.system_type_id IN (231,239)
THEN CASE WHEN c.max_length <> -1
THEN '(' + CAST(c.max_length/2 AS varchar(7)) + ')'
ELSE '(max)' END
ELSE
CASE WHEN c.system_type_id IN (41,42,43)
THEN '(' + CAST(c.scale AS varchar(7)) + ')'
ELSE
CASE WHEN c.system_type_id IN (106,108)
THEN '(' + CAST(c.precisiON AS varchar(7)) + ',' + CAST(c.scale AS varchar(7)) + ')'
ELSE ''
END
END
END
+ CASE WHEN c.is_nullable = 1 THEN ' NULL' ELSE ' NOT NULL' END
FROM tempdb.sys.columns c
JOIN tempdb..sysobjects o ON (c.object_id = o.id)
JOIN tempdb.sys.types t ON (t.user_type_id = c.user_type_id)
WHERE o.name LIKE '#tmp99%'
UNION ALL SELECT ')'
FOR XML PATH('')
DROP TABLE #tmp99
答案 1 :(得分:0)
我试图实现这个目标,但它变得太难了。让我说说我是如何接近它的。我使用了SQL解析器:http://www.sqlparser.com/download.php和C#。然后试着分析文字。对于简单的查询,这没关系,但很快就会变得太复杂了。关于视图的想法看起来更简单。