从SQL Server 2008中的任意sql语句中获取数据类型

时间:2010-04-01 18:03:33

标签: sql sql-server tsql sql-server-2008

给定一些任意SQL我想获取返回列的数据类型。该语句可能会连接许多表,视图,TVF等。我知道我可以根据查询创建一个视图并从中获取数据类型,希望有更快的方法。只是认为我能够想到的是编写.net实用程序来运行SQL并检查结果,想知道是否有TSQL答案。


给出(不是真正的表只是一个例子)

SELECT p.Name AS PersonName, p.Age, a.Account as AccountName
FROM Person as p
LEFT JOIN Account as a
    ON p.Id = a.OwnerId

我想要像

这样的东西

PersonName :( nvarchar(255),not null)

年龄:( smallInt,not null)

等...

2 个答案:

答案 0 :(得分:1)

    /*you may have to alias some columns if they are not unique*/
    /*EDIT: added fix for 2byte nchar/nvarchar */
    SELECT top (1)  /*<your query columns here>*/ 
    INTO #tmp99
    /*<rest of your query here>*/


    SELECT 'CREATE TABLE [tablename]('  UNION ALL 
    SELECT CASE WHEN ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) = 1 THEN '' ELSE ',' END 
    + CHAR(13) + '[' + c.name + '] [' + t.name + ']' 
    + CASE WHEN c.system_type_id IN (165,167,173,175) 
           THEN CASE WHEN c.max_length <> -1
                     THEN '(' + CAST(c.max_length AS varchar(7)) + ')' 
                     ELSE '(max)' 
                     END 
           WHEN c.system_type_id IN (231,239) 
           THEN CASE WHEN c.max_length <> -1 
                     THEN '(' + CAST(c.max_length/2 AS varchar(7)) + ')' 
                     ELSE '(max)' END
           ELSE 
               CASE WHEN c.system_type_id IN (41,42,43) 
                    THEN '(' + CAST(c.scale AS varchar(7)) + ')'
                    ELSE
                        CASE WHEN c.system_type_id IN (106,108) 
                             THEN '(' + CAST(c.precisiON AS varchar(7)) + ',' + CAST(c.scale AS varchar(7)) + ')'
                             ELSE ''
                             END 
                    END
           END

    + CASE WHEN c.is_nullable = 1 THEN ' NULL' ELSE ' NOT NULL' END 

    FROM tempdb.sys.columns c
    JOIN tempdb..sysobjects o ON (c.object_id = o.id)
    JOIN tempdb.sys.types t ON (t.user_type_id = c.user_type_id)
    WHERE o.name LIKE '#tmp99%' 
    UNION ALL SELECT ')' 
    FOR XML PATH('')

    DROP TABLE #tmp99

答案 1 :(得分:0)

我试图实现这个目标,但它变得太难了。让我说说我是如何接近它的。我使用了SQL解析器:http://www.sqlparser.com/download.php和C#。然后试着分析文字。对于简单的查询,这没关系,但很快就会变得太复杂了。关于视图的想法看起来更简单。