我想检查，如果日期是今天，明天，昨天或其他。 但我的代码不起作用。
代码：
$timestamp = "2014.09.02T13:34";
$date = date("d.m.Y H:i");
$match_date = date('d.m.Y H:i', strtotime($timestamp));
if($date == $match_date) {
//Today
} elseif(strtotime("-1 day", $date) == $match_date) {
//Yesterday
} elseif(strtotime("+1 day", $date) == $match_date) {
//Tomorrow
} else {
//Sometime
}
“守则”总是出现在其他情况下。
答案 0 :(得分：38)
首先。您在使用函数strtotime时出错，请参阅PHP documentation
int strtotime ( string $time [, int $now = time() ] )
您需要修改代码以将整数时间戳传递给此函数。
第二。您使用包含时间部分的格式 d.m.Y H：i 。如果您只想比较日期，则必须删除时间部分，例如`$ date = date（＆＃34; d.m.Y＆＃34;）;``
第三。我不确定它是否以相同的方式运行，但我的PHP不了解$timestamp的日期格式并返回 01.01。 1970 02:00 进入$match_date
$timestamp = "2014.09.02T13:34";
date('d.m.Y H:i', strtotime($timestamp)) === "01.01.1970 02:00";
您需要检查strtotime($timestamp)是否返回正确的日期字符串。如果不是，则需要指定$timestamp变量中使用的格式。您可以使用date_parse_from_format或DateTime::createFromFormat
这是一个工作示例：
$timestamp = "2014.09.02T13:34";
$today = new DateTime(); // This object represents current date/time
$today->setTime( 0, 0, 0 ); // reset time part, to prevent partial comparison
$match_date = DateTime::createFromFormat( "Y.m.d\\TH:i", $timestamp );
$match_date->setTime( 0, 0, 0 ); // reset time part, to prevent partial comparison
$diff = $today->diff( $match_date );
$diffDays = (integer)$diff->format( "%R%a" ); // Extract days count in interval
switch( $diffDays ) {
case 0:
echo "//Today";
break;
case -1:
echo "//Yesterday";
break;
case +1:
echo "//Tomorrow";
break;
default:
echo "//Sometime";
}
答案 1 :(得分：21)
<?php
$current = strtotime(date("Y-m-d"));
$date = strtotime("2014-09-05");
$datediff = $date - $current;
$difference = floor($datediff/(60*60*24));
if($difference==0)
{
echo 'today';
}
else if($difference > 1)
{
echo 'Future Date';
}
else if($difference > 0)
{
echo 'tomarrow';
}
else if($difference < -1)
{
echo 'Long Back';
}
else
{
echo 'yesterday';
}
?>
答案 2 :(得分：10)
我认为这会对你有所帮助：
<?php
$date = new DateTime();
$match_date = new DateTime($timestamp);
$interval = $date->diff($match_date);
if($interval->days == 0) {
//Today
} elseif($interval->days == 1) {
if($interval->invert == 0) {
//Yesterday
} else {
//Tomorrow
}
} else {
//Sometime
}
答案 3 :(得分：6)
在Php中没有内置函数（羞耻^^）。您想要将日期字符串与今天进行比较，您可以使用简单的if (substr($timestamp, 0, 10) === date('Y.m.d')) { today }
elseif (substr($timestamp, 0, 10) === date('Y.m.d', strtotime('-1 day')) { yesterday }
来实现它：
{{1}}
没有日期转换，简单。
答案 4 :(得分：5)
function getRangeDateString($timestamp) {
if ($timestamp) {
$currentTime=strtotime('today');
// Reset time to 00:00:00
$timestamp=strtotime(date('Y-m-d 00:00:00',$timestamp));
$days=round(($timestamp-$currentTime)/86400);
switch($days) {
case '0';
return 'Today';
break;
case '-1';
return 'Yesterday';
break;
case '-2';
return 'Day before yesterday';
break;
case '1';
return 'Tomorrow';
break;
case '2';
return 'Day after tomorrow';
break;
default:
if ($days > 0) {
return 'In '.$days.' days';
} else {
return ($days*-1).' days ago';
}
break;
}
}
}
答案 5 :(得分：0)
将日期传递给函数。
<?php
function getTheDay($date)
{
$curr_date=strtotime(date("Y-m-d H:i:s"));
$the_date=strtotime($date);
$diff=floor(($curr_date-$the_date)/(60*60*24));
switch($diff)
{
case 0:
return "Today";
break;
case 1:
return "Yesterday";
break;
default:
return $diff." Days ago";
}
}
?>
答案 6 :(得分：0)
此处是已接受答案的更详尽的版本。 它仅接受时间戳记，并在所有+/- 2天之内返回一个相对日期或格式化的日期字符串
<?php
/**
* Relative time
*
* date Format http://php.net/manual/en/function.date.php
* strftime Format http://php.net/manual/en/function.strftime.php
* latter can be used with setlocale(LC_ALL, 'de_DE@euro', 'de_DE', 'deu_deu');
*
* @param timestamp $target
* @param timestamp $base start time, defaults to time()
* @param string $format use date('Y') or strftime('%Y') format string
* @return string
*/
function relative_time($target, $base = NULL, $format = 'Y-m-d H:i:s')
{
if(is_null($base)) {
$base = time();
}
$baseDate = new DateTime();
$targetDate = new DateTime();
$baseDate->setTimestamp($base);
$targetDate->setTimestamp($target);
// don't modify original dates
$baseDateTemp = clone $baseDate;
$targetDateTemp = clone $targetDate;
// normalize times -> reset to midnight that day
$baseDateTemp = $baseDateTemp->modify('midnight');
$targetDateTemp = $targetDateTemp->modify('midnight');
$interval = (int) $baseDateTemp->diff($targetDateTemp)->format('%R%a');
d($baseDate->format($format));
switch($interval) {
case 0:
return (string) 'today';
break;
case -1:
return (string) 'yesterday';
break;
case 1:
return (string) 'tomorrow';
break;
default:
if(strpos($format,'%') !== false )
{
return (string) strftime($format, $targetDate->getTimestamp());
}
return (string) $targetDate->format($format);
break;
}
}
setlocale(LC_ALL, 'de_DE@euro', 'de_DE', 'deu_deu');
echo relative_time($weather->time, null, '%A, %#d. %B'); // Montag, 6. August
echo relative_time($weather->time, null, 'l, j. F'); // Monday, 6. August
答案 7 :(得分：0)
这对我有用，我想只在日期是今天和前一天才显示关键字“今天”或“昨天”，否则以d-M-Y格式显示日期
<?php
function findDayDiff($date){
$param_date=date('d-m-Y',strtotime($date);
$response = $param_date;
if($param_date==date('d-m-Y',strtotime("now"))){
$response = 'Today';
}else if($param_date==date('d-m-Y',strtotime("-1 days"))){
$response = 'Yesterday';
}
return $response;
}
?>
答案 8 :(得分：0)
function get_when($date) {
$current = strtotime(date('Y-m-d H:i'));
$date_diff = $date - $current;
$difference = round($date_diff/(60*60*24));
if($difference >= 0) {
return 'Today';
} else if($difference == -1) {
return 'Yesterday';
} else if($difference == -2 || $difference == -3 || $difference == -4 || $difference == -5) {
return date('l', $date);
} else {
return ('on ' . date('jS/m/y', $date));
}
}
get_when(date('Y-m-d H:i', strtotime($your_targeted_date)));