将JSON DeSerialize转换为C＃对象：如何处理缺失的属性

Question

我遇到问题，我的JSON对象不包含C＃对象（DataMember）中可用的所有属性。

在反序列化JSON时，有什么方法可以忽略缺少的属性

/// <summary>
        /// Deserializes a stream that contains a json text into an object.
        /// </summary>
        /// <typeparam name="T">The type of the object to be deserialized into.</typeparam>
        /// <param name="stream">The stream that contains the json text representation of the object.</param>
        /// <returns>A deserialized object.</returns>
        public static T DeserializeJson<T>(Stream stream) where T : class 
        {
            DataContractJsonSerializerSettings settings = new DataContractJsonSerializerSettings();
            settings.UseSimpleDictionaryFormat = true;

            DataContractJsonSerializer jsonSerializer = new DataContractJsonSerializer(typeof(T), settings);
            return jsonSerializer.ReadObject(stream) as T;
        }

Answer 1

您可以为IsRequired指定DataMemberAttribute属性。 如果将其设置为false，则如果json中缺少此成员，则反序列化不会抛出异常。

    [DataMember( IsRequired = false )]
    public bool ManualSessionClose { get; set; }