我需要从html中删除特定的类名,例如:
<table class="removeme"></table>
我需要一个可以删除指定类的代码剪切&#34; removeme&#34;和清洁后的HTML将如下所示:
<table></table>
还要记住,传递的html可以包含类似的内容:
<table class="removeme leaveme"></table>
清洁后应显示为:
<table class="leaveme"></table>
答案 0 :(得分:2)
您可以尝试分两步解决这个问题,首先让所有节点只有'removeme`类属性,然后从中删除整个类属性:
//*[normalize-space(@class)='removeme']
然后在下一步中,获取具有removeme
类和其他一些类的所有节点,然后从类属性中删除removeme
:
//*[
normalize-space(@class)!='removeme'
and
contains(concat(' ', normalize-space(@class), ' '), ' removeme ')
]
上面XPath中的第一个条件意味着获取步骤1中未处理的所有节点,第二个条件为the equivalent XPath for css selector .removeme
以下是完整的控制台示例:
var xml = @"<root>
<table class=""removeme""></table>
<table class=""removeme leaveme""></table>
<table class="" removeme ""></table>
</root>";
var doc = new HtmlDocument();
doc.LoadHtml(xml);
var removemeOnly = doc.DocumentNode.SelectNodes("//*[normalize-space(@class)='removeme']");
foreach (HtmlNode node in removemeOnly)
{
node.Attributes["class"].Remove();
}
var containsRemoveme =
doc.DocumentNode.SelectNodes("//*[normalize-space(@class)!='removeme' and contains(concat(' ', normalize-space(@class), ' '), ' removeme ')]");
foreach (HtmlNode node in containsRemoveme)
{
node.Attributes["class"].Value = node.Attributes["class"].Value.Replace("removeme", "");
}
//print formatted HTML output (don't use this for non XML-compliant HTML)
Console.WriteLine(XDocument.Parse(doc.DocumentNode.OuterHtml));