触发MySQL的结果集

时间:2014-09-02 10:01:14

标签: mysql sql

这是我第一次使用触发器,我遇到了一些麻烦。 我创建了一个通知系统,当创建新通知时,它会向notify表添加一行。添加的内容取决于它的通知类型。

到目前为止,我已尝试过:

DELIMITER $$
DROP TRIGGER IF EXISTS generate_notify $$
CREATE TRIGGER generate_notify
AFTER INSERT 
ON notifications
FOR EACH ROW
BEGIN

SELECT @group := notify_group FROM notification_types WHERE type=NEW.type;
IF (@group <> 1) THEN
INSERT INTO notify (user_id, notification_id) VALUES (NEW.user_reference, NEW.id);
ELSE

INSERT INTO notify (user_id, notification_id) VALUES(
    SELECT ID, NEW.id FROM user_customer WHERE clientID=NEW.user_reference
);
END IF;
END; $$
DELIMITER ;

我四处搜索,然后将其更改为:

DELIMITER $$
DROP TRIGGER IF EXISTS generate_notify $$
CREATE TRIGGER generate_notify
AFTER INSERT 
ON notifications
FOR EACH ROW
BEGIN
DECLARE insert_user_id INT(11);
SELECT @group := notify_group FROM notification_types WHERE type=NEW.type;
IF (@group <> 1) THEN
INSERT INTO notify (user_id, notification_id) VALUES (NEW.user_reference, NEW.id);
ELSE
SELECT ID INTO insert_user_id FROM user_customer WHERE clientID=NEW.user_reference;
INSERT INTO notify (user_id, notification_id) VALUES(insert_user_id, NEW.id);
END IF;
END; $$
DELIMITER ;

我也尝试过将上面的内容混合起来,所有我得到的都是无法返回结果集,或者我的选择查询存在语法错误。

(另外,我假设为触发器预定义了NEW关键字?)

1 个答案:

答案 0 :(得分:1)

您的第一次尝试实际上是在正确的轨道上,但您没有将SELECT的结果写入变量。无法从触发器返回结果集。

DELIMITER $$
DROP TRIGGER IF EXISTS generate_notify $$
CREATE TRIGGER generate_notify
AFTER INSERT 
ON notifications
FOR EACH ROW
BEGIN

DECLARE v_group INT;

SELECT notify_group INTO v_group FROM notification_types WHERE type=NEW.type;
IF (v_group <> 1) THEN
    INSERT INTO notify (user_id, notification_id) VALUES (NEW.user_reference, NEW.id);
ELSE
    INSERT INTO notify (user_id, notification_id) VALUES(
    SELECT ID, NEW.id FROM user_customer WHERE clientID=NEW.user_reference
);
END IF;
END $$
DELIMITER ;