Question

我确定我昨晚发布了这个，但我找不到，我的帐户说我已经问了0个问题。反正...

我的MySQL数据库中有一个包含英国县的字段。我想在下拉框中列出这些内容，以便用户可以选择这些内容，以便选择他们想要查看结果的英国区域。

到目前为止，我有这个...但我的下拉框显示为空？

任何帮助都非常感激。

<?php
include 'connect.php';

//set variable
$option = '';

// Get the county names from database - no duplicates
$query = "SELECT DISTINCT tradingCounty FROM offers";

// execute the query, $result will hold all of the Counties in an array
$result = mysqli_query($con,$query);


while($row = mysql_fetch_array($result)) {
    $option .="<option>" . $row['tradingCounty'] . "</option>";
    echo $option;
}

echo "<form id='filter' name='filter' method='post' action='resultssimple.php'>
        <p><label>County</label></p>
        <select name='filter' id='filter'>" . $option . "</select>
        </form>";
?>

Answer 1

试试这个......

while($row = mysql_fetch_array($result)) {
    $option .="<option value='". $row['tradingCounty'] .  '">" . $row['tradingCounty'] . "</option>"; 
}

您不会在while循环中回显该选项，并且需要选项value属性。

Answer 2

你能试试吗

    echo "<form id='filter' name='filter' method='post' action='resultssimple.php'>
            <p><label>County</label></p>
            <select name='filter' id='filter'>";
                // Get the county names from database - no duplicates
                $query = "SELECT DISTINCT tradingCounty FROM offers";

        // execute the query, $result will hold all of the Counties in an array
        $result = mysqli_query($con,$query);
        while($row = mysql_fetch_array($result)) {
            $option .="<option>" . $row['tradingCounty'] . "</option>";
            echo $option;
        }

    echo "</select>
    </form>";

Answer 3

$result = $mysqli->query($query); while($row = $result->fetch_array()) { $rows[] = $row; } 使用mysqli的上述代码语法。

mysql数据库作为下拉列表/ php的不同结果

3 个答案: