Question

对于我的项目，我们使用SQL 2008连接。这非常有效。查询在不给出db或PHP错误的情况下停止运行。这对我来说很奇怪。我做的模型功能是：

function getTankDataByYear($year,$flexxis_tabel){                   

    $querytext = "
    SELECT  
        deduction.[Taxation code] AS deduction,
        costkindfuel.[Fuel Type] AS fueltype,
        leasecar.[Fuel Tank Volume] AS tankvolume,          
        leasecardriver.[License] AS kenteken,                                   
        leasecardriver.[Driver Code] AS personeelsnummer,       
        fuel.[Perpetration Date] AS dates,
        fuel.[Perpetration Time] AS times,
        fuel.[Perpetration Date] AS tankdatum,
        fuel.[Volume liters] AS liters,
        fuel.[License No_] AS pk1,
        fuel.[Perpetration Date] AS pk2,
        fuel.[Perpetration Time] AS pk3,        
        fuel.[Costkind lease company] AS pk4,
        fuel.[KM Reliable] AS kmreliable,
        fuel.[Replacement Transport] AS vervangendvervoer,
        fuel.[High Way] AS snelweg
    FROM [".$flexxis_tabel."\$Fuel Table] AS fuel                                                                   
    LEFT JOIN [".$flexxis_tabel."\$Lease Car Driver] AS leasecardriver ON leasecardriver.[License] = fuel.[License No_]
    LEFT JOIN [".$flexxis_tabel."\$Lease Car] AS leasecar ON leasecar.[License No_] = leasecardriver.[License]
    LEFT JOIN [Costkind Fuel] AS costkindfuel ON costkindfuel.[Costkind Fuel] = fuel.[Costkind lease company]
    LEFT JOIN [".$flexxis_tabel."\$Deduction table] AS deduction ON deduction.[Driver code] = leasecardriver.[Driver Code]
        AND (YEAR(Deduction.[Ending Date]) >= '".$year."' 
        OR YEAR(Deduction.[Ending Date]) = '1753')
        AND YEAR(Deduction.[Starting Date]) <= '".$year."'      
    WHERE YEAR(fuel.[Perpetration Date]) = '".$year."'
    ";

    $query = $this->db->query($querytext)->result();
    return $query;
}

$ flexxis_tabel是该公司的名称。

当我直接在SQL db中运行它时，此查询很有效。找到所有联接并且正确填充选择数据。但是当我在Codeigniter中运行这个查询时 PHP脚本像骰子一样停止工作。

当我查看Codeigniter的核心时，它会在调用此核心函数时停止运行：系统/数据库/驱动程序/ mssql_result.php

/**
 * Result - object
 *
 * Returns the result set as an object
 *
 * @access  private
 * @return  object
 */
function _fetch_object()
{
    return mssql_fetch_object($this->result_id);
}

这是Codeigniter的错误吗？我可以尝试做什么？

P.S。当删除选择的前五行时查询运行良好，但我需要这些字段，并且根据SQL程序连接是oké..

行：

    leasecar.[Fuel Tank Volume] AS tankvolume,  
    deduction.[Taxation code] AS deduction,
    costkindfuel.[Fuel Type] AS fueltype,
    leasecar.[Fuel Tank Volume] AS tankvolume,          
    leasecardriver.[License] AS kenteken,                                   
    leasecardriver.[Driver Code] AS personeelsnummer,

- 编辑 - 我使用GitHub的Codeigniter 2.2最新版本。

Answer 1

您有两个不同的列别名AS tankvolume。 MSSQL并不关心（这就是在sqlcmd或ssms中执行时查询工作正常的原因），但PHP确实如此，因为它不知道将哪些值分配给->tankvolume属性。尝试重命名其中一个。

或者，因为在这种特殊情况下，它是同一列两次，只需删除第二个副本：

 leasecar.[Fuel Tank Volume] AS tankvolume,

Codeigniter SQL查询确实停止运行

1 个答案: