Question

我正在使用此问题（https://stackoverflow.com/a/13854813）的答案，根据特定长度将大字符串拆分为数组。

- (NSArray *) componentSaparetedByLength:(NSUInteger) length{
        NSMutableArray *array = [NSMutableArray new];
        NSRange range = NSMakeRange(0, length);
        NSString *subString = nil;
        while (range.location + range.length <= self.length) {
            subString = [self substringWithRange:range];
            [array addObject:subString];
            //Edit
            range.location = range.length + range.location;
            //Edit
            range.length = length;
        }

        if(range.location<self.length){
            subString = [self substringFromIndex:range.location];
            [array addObject:subString];
        }
        return array;
}

我想让它只拆分空格上的字符串。所以，如果子串的最后一个字符不是空格，我希望它缩短子字符串直到最后一个字符是一个空格（希望这是有意义的）。基本上我想要分割字符串，但不要在过程中拆分。

有什么建议吗？

Answer 1

可能您可以与componentsSeparatedByCharactersInSet:分开并重新构建行。

但在你的情况下，我认为你最好迭代unichar s。

NSMutableArray *result = [NSMutableArray array];

NSUInteger charCount = string.length;
unichar *chars = malloc(charCount*sizeof(unichar));
if(chars == NULL) {
    return nil;
}
[string getCharacters:chars];
unichar *cursor = chars;
unichar *lineStart = chars;
unichar *wordStart = chars;
NSCharacterSet *whitespaces = [NSCharacterSet whitespaceCharacterSet];

while(cursor < chars+charCount) {
    if([whitespaces characterIsMember:*cursor]) {
        if(cursor - lineStart >= length) {
            NSString *line = [NSString stringWithCharacters:lineStart length:wordStart - lineStart];
            [result addObject:line];
            lineStart = wordStart;
        }
        wordStart = cursor + 1;
    }
    cursor ++;
}
if(lineStart < cursor) {
    [result addObject:[NSString stringWithCharacters:lineStart length: cursor - lineStart]];
}
free(chars);
return result;

输入：

@"I would like to make this only split the string on a space. So, if the last character of the substring is not a space, I would like it it shorten that substring until the last character is a space (hopefully that makes sense). Basically I want this to split the string, but not split words in the process."

输出（长度== 30）：

(
    "I would like to make this ",
    "only split the string on a ",
    "space. So, if the last ",
    "character of the substring is ",
    "not a space, I would like it ",
    "it shorten that substring ",
    "until the last character is a ",
    "space (hopefully that makes ",
    "sense). Basically I want this ",
    "to split the string, but not ",
    "split words in the process."
)

按常数分割字符串，仅在空格上

1 个答案: