Question

IF NOT EXISTS(SELECT * FROM Employee where code = 'testcode1')
INSERT INTO 
    Employee(code, fname, lname)
VALUES
('testcode1', 'testfn', testln')
ELSE
    RAISERROR (SELECT * FROM Employee where code = 'testcode1', 11, 1)

如果数据已存在于不在网格中的消息中，我如何返回结果？

示例输出

  Code         fname     lname
 ------------- --------  -----------
  tescode1      testfn   testln

Answer 1

你可以将它放在一个消息变量中并提高它。例如：

DECLARE @Message varchar(200)

IF NOT EXISTS(SELECT * FROM Employee where code = 'testcode1')
BEGIN
    INSERT INTO 
    Employee(code, fname, lname)
    VALUES
    ('testcode1', 'testfn', 'testln')
END
ELSE
BEGIN
    SELECT @Message = FNAME + ' ' + LNAME FROM Employee where code = 'testcode1'
    RAISERROR (@Message, 11, 1)
END

在Message而不是Grid中返回数据

1 个答案: