Question

我有一个listview，我会将他的全部数据保存在sqLite数据库中。我已经得到了帮助，但我无法通过一个简单的按钮将数据保存在数据库中;只需点击＆＃34;保存列表＆＃34;按钮应该保存整个列表，只是为了看，可能在LogCat中检索结果..这是帮手

`public class SqlHelper扩展了SQLiteOpenHelper {

// All Static variables
// Database Version
private static final int DATABASE_VERSION = 1;

// Database Name
private static final String DATABASE_NAME = "MyDatabase";

// Database table name
private static final String TABLE_LIST = "MyListItem";

// Table Columns names
private static final String KEY_ID = "id";
private static final String KEY_ListItem = "listitem";

public SqlHelper(Context context) {
    super(context, DATABASE_NAME, null, DATABASE_VERSION);
}

// Creating Tables
@Override
public void onCreate(SQLiteDatabase db) {
    String CREATE_LIST_TABLE = "CREATE TABLE " + TABLE_LIST + "(" + KEY_ID
        + " INTEGER," + KEY_ListItem + " TEXT" + ")";

    db.execSQL(CREATE_LIST_TABLE);
}

// Upgrading database
@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
    // Drop older table if existed
    db.execSQL("DROP TABLE IF EXISTS " + TABLE_LIST);

    // Create tables again
    onCreate(db);
}
void addListItem(ArrayList<String> listItem) {
    SQLiteDatabase db = this.getWritableDatabase();

    ContentValues values = new ContentValues();
    for (int i = 0; i < listItem.size(); i++) {

        Log.e("value inserting==", "" + listItem.get(i));
        values.put(KEY_ListItem, listItem.get(i));
        db.insert(TABLE_LIST, null, values);

    }

    db.close(); // Closing database connection
}

Cursor getListItem() {
    String selectQuery = "SELECT  * FROM " + TABLE_LIST;

    SQLiteDatabase db = this.getWritableDatabase();
    Cursor cursor = db.rawQuery(selectQuery, null);

    return cursor;
}

}`

我尝试在onClick中编写db.addListItem(titles);例如..标题是：ArrayList<String> titles;但它崩溃了......我认为它不正确。有什么帮助吗？

以sqLite保存imageview数据

0 个答案: