Question

我做错了什么？
它返回以下错误：
This version of MySQL doesn't yet support 'LIMIT & IN/ALL/ANY/SOME subquery'
当我单独运行子查询时，子查询工作正常：

select * from emprego 
where base in 
(
  SELECT base FROM emprego me
  group by base
  order by sum(TIMEDIFF(me.data_demissao,me.data_admissao)) desc
  limit 1
)

Answer 1

使用自联接重写您的查询

select e.* 
from emprego e
join  
(
  SELECT base FROM emprego me
  group by base
  order by sum(TIMEDIFF(me.data_demissao,me.data_admissao)) desc
  limit 1
) e1
on(e.base = e1.base)

Answer 2

试试这个

select * from emprego
where base in
(
    select * from 
    (
        select base from emprego me
        group by base
        order by sum(TIMEDIFF(me.data_demissao, me.data_admissao)) desc
        limit 1
    ) as t
)

我希望这会有所帮助。

Answer 3

这是一个查询命题：

SELECT *
FROM emprego E
INNER JOIN (SELECT E2.base
                 ,SUM(TIMEDIFF(E2.data_demissao, E2.data_admissao)) AS [duree]
            FROM emprego E2
            GROUP BY E2.base) D ON D.base = E.base
ORDER BY D.duree DESC
LIMIT 1

希望这可以帮助您避免在执行查询时出错。

对子查询使用限制

3 个答案: