我想在一个查询中组合不同的Count语句,以便最终查询只返回每个Count的一个数字(总数)。
以下查询单独工作,但我找不到一种方法来组合它们而不重复相同的结果(嵌套表),并且不会丢失每个查询的单独名称(Union All)。
有人可以告诉我如何实现这个目标吗?
我的SQL(这里只是为了更方便的视图而组合):
(
SELECT COUNT(*) OVER() AS countB
FROM MOC_Log2 B
WHERE B.modBy = @modBy
AND B.lastUpdate = 'Added'
FOR XML PATH(''), ELEMENTS, TYPE
),
(
SELECT COALESCE(SUM(D.vote), '0') AS countC
FROM MOC_Log3 C
LEFT JOIN MOC_Log3_Votes D
ON D.itemID = C.itemID
WHERE C.modBy = @modBy
AND C.lastUpdate = 'Added'
FOR XML PATH(''), ELEMENTS, TYPE
),
(
SELECT COALESCE(SUM(F.vote), '0') AS countE
FROM MOC_Log4 E
LEFT JOIN MOC_Log4_Votes F
ON F.itemID = E.itemID
WHERE E.modBy = @modBy
AND E.lastUpdate = 'Added'
FOR XML PATH(''), ELEMENTS, TYPE
)
非常感谢你提供任何帮助,蒂姆。
答案 0 :(得分:1)
只需添加空列?
SELECT COUNT(*) OVER() AS countB,
Null AS countC,
Null AS countE
FROM MOC_Log2 B
WHERE B.modBy = @modBy
AND B.lastUpdate = 'Added'
FOR XML PATH(''), ELEMENTS, TYPE
Union
SELECT null,
COALESCE(SUM(D.vote), '0'),
null
FROM MOC_Log3 C
LEFT JOIN MOC_Log3_Votes D
ON D.itemID = C.itemID
WHERE C.modBy = @modBy
AND C.lastUpdate = 'Added'
FOR XML PATH(''), ELEMENTS, TYPE
Union
SELECT null,
null,
COALESCE(SUM(F.vote), '0')
FROM MOC_Log4 E
LEFT JOIN MOC_Log4_Votes F
ON F.itemID = E.itemID
WHERE E.modBy = @modBy
AND E.lastUpdate = 'Added'
FOR XML PATH(''), ELEMENTS, TYPE
另请注意我使用Union over Union all。很难说这是否适合你,因为我无法判断额外的空列是否会导致一些错误。