Question

我在Alfresco中有一个Web脚本，当我在HTTP请求中传入正确的参数时，它可以工作。我添加了类似于此代码段（source）的验证。

如果我发现我的验证步骤失败，我该怎么告诉Alfresco停止处理webscript？（如果可能的话，我想在没有else块的情况下这样做。）

// extract folder listing arguments from URI
var verbose = (args.verbose == "true" ? true : false);
var folderpath = url.templateArgs.folderpath;

// search for folder within Alfresco content repository
var folder = roothome.childByNamePath(folderpath);

// validate that folder has been found
if (folder == undefined || !folder.isContainer) {
   status.code = 404;
   status.message = "Folder " + folderpath + " not found.";
   status.redirect = true;
   // ********* HOW DO I TELL ALFRESCO TO STOP PROCESSING HERE? ************
}

// perform some business logic with the parameters that passed validation......
// ********* I DO NOT WANT TO COME HERE IF VALIDATION FAILS ************

// construct model for response template to render
model.verbose = verbose;
model.folder = folder;

Answer 1

这里的技巧是将代码包装在一个函数中（通常按惯例称为main）。如果要停止处理，只需调用该函数并从该函数返回。像这样：

function main() {
  // extract folder listing arguments from URI
  var verbose = (args.verbose == "true" ? true : false);
  var folderpath = url.templateArgs.folderpath;

  // search for folder within Alfresco content repository
  var folder = roothome.childByNamePath(folderpath);
  // validate that folder has been found
  if (folder == undefined || !folder.isContainer) {
    status.code = 404;
    status.message = "Folder " + folderpath + " not found.";
    status.redirect = true;
    return;
  }
  // Do stuff with the folder

}

main();

Alfresco网页脚本：如何提前停止处理或返回？

1 个答案: