Question

我需要动态排除定义的POJO列表中的某些属性。要序列化的主要POJO是：

public class Foo
{
    List<Bar> bar;

    public void setBar(List<Bar> bar)
    {
        this.bar = bar;
    }

    public List<Bar> getBar()
    {
        return this.bar;
    }

    public static class Bar
    {
        private int id;
        private boolean ignoreId;
        private String name;

        public void setId(int id)
        {
            this.id = id;
        }

        public int getId()
        {
            return this.id;
        }

        public void setIgnoreId(boolean ignoreId)
        {
            this.ignoreId = ignoreId;
        }

        public boolean isIgnoreId()
        {
            return this.ignoreId;
        }

        public void setName(String name)
        {
            this.name = name;
        }

        public String getName()
        {
            return this.name;
        }
    }
}

如果ignoreId = true，则忽略

id，如下所示：

[
    { "id": "1", "name": "one" },
    { "name": "two" }
    { "name": "three" }
    { "id": "4", "name": "four" }
]

目前，我已尝试使用JsonFilter和JacksonJsonViews，但无法获得所需的输出。如果有任何指针可以实现这一点，我会很高兴。

Answer 1

您应该编写一个自定义Jackson filter，它会根据其他属性值过滤掉POJO属性。您应该覆盖PropertyFilter.serializeAsField()方法以访问序列化对象的实例。这是一个例子：

public class JacksonFilter2 {
    @JsonFilter("filter")
    public static class Bar {
        public final int id;
        @JsonIgnore
        public final boolean ignoreId;
        public final String name;

        public Bar(int id, boolean ignoreId, String name) {
            this.id = id;
            this.ignoreId = ignoreId;
            this.name = name;
        }
    }

    public static class ExcludeIdFilter extends SimpleBeanPropertyFilter {

        @Override
        protected boolean include(BeanPropertyWriter writer) {
            return true;
        }

        @Override
        protected boolean include(PropertyWriter writer) {
            return true;
        }

        @Override
        public void serializeAsField(Object pojo,
                                     JsonGenerator jgen,
                                     SerializerProvider provider,
                                     PropertyWriter writer) throws Exception {
            if (pojo instanceof Bar
                    && "id".equals(writer.getName())
                    && ((Bar) pojo).ignoreId) {
               writer.serializeAsOmittedField(pojo, jgen, provider);
            } else {
                super.serializeAsField(pojo, jgen, provider, writer);
            }
        }
    }

    public static void main(String[] args) throws JsonProcessingException {
        List<Bar> bars = Arrays.asList(new Bar(1, false, "one"),  new Bar(2, true, "two"));
        ObjectMapper mapper = new ObjectMapper();
        mapper.setFilters(new SimpleFilterProvider().addFilter("filter", new ExcludeIdFilter()));
        System.out.println(mapper.writerWithDefaultPrettyPrinter().writeValueAsString(bars));
    }

}

输出：

[ {
  "id" : 1,
  "name" : "one"
}, {
  "name" : "two"
} ]

Answer 2

我正在使用Jackson 2.4.2。

模型对象是：

public class PostProject
{
    /* The field template of this project */
    private List< FieldTemplateObject > field_templates;

    /**
     * @author Damilola Okuboyejo
     */
    @JsonFilter( "FieldTemplateIdFilter" )
    public static class FieldTemplateObject
    {
      private int     id;
      private boolean is_inherited;
      private String  item_type;

      /**
       * @return the id
       */
      public int getId()
      {
         return id;
      }

      /**
       * @param id
       *           the id to set
       */
      public void setId( int id )
      {
         this.id = id;
      }

      /**
       * @return the is_inherited
       */
      public boolean isIs_inherited()
      {
         return is_inherited;
      }

      /**
       * @param is_inherited
       *           the is_inherited to set
       */
      public void setIs_inherited( boolean is_inherited )
      {
         this.is_inherited = is_inherited;
      }

      /**
       * @return the item_type
       */
      public String getItem_type()
      {
         if( item_type == null )
         {
            item_type = PostProject.item_type;
         }
         return item_type;
      }

      /**
       * @param item_type
       *           the item_type to set
       */
      public void setItem_type( String item_type )
      {
         this.item_type = item_type;
      }
   }
}

Myy序列化器就像这样：

public static class ModelFieldSerializer extends SimpleBeanPropertyFilter
{
  @Override
  protected boolean include( BeanPropertyWriter writer )
  {
     return true;
  }

  @Override
  protected boolean include( PropertyWriter writer )
  {
     return true;
  }

  @Override
  public void serializeAsField( Object pPojo, JsonGenerator pJgen,
        SerializerProvider pProvider, PropertyWriter pWriter )
        throws Exception
  {
     if( pPojo instanceof FieldTemplateObject )
     {
        if( ("id".equals( pWriter.getName() ))
              && ((FieldTemplateObject) pPojo).isIs_inherited() )
        {
           pWriter.serializeAsOmittedField( pPojo, pJgen, pProvider );
        }
        else
        {
           super.serializeAsField( pPojo, pJgen, pProvider, pWriter );
        }
     }
  }
}

注意：模型类在客户端 - 服务器体系结构env

中通过网络传递

Answer 3

我刚看到罪魁祸首。非常感谢@Alexey和我一起住在这里。经过多次尝试，我发现Jackson 2.4.2可能要求我将我的系列设备放在它可以使用的模型中。我想知道为什么，但可能是由于Java对象序列化要求，杰克逊未能在运行时映射过滤器。我希望Tatu会在Jackson文档中注意到这一点

public class PostProject
{
    /* The field template of this project */
    private List< FieldTemplateObject > field_templates;

    /**
     * @author Damilola Okuboyejo
     */
    @JsonFilter( "FieldTemplateIdFilter" )
    public static class FieldTemplateObject
    {
      private int     id;
      private boolean is_inherited;
      private String  item_type;

      /**
       * @return the id
       */
      public int getId()
      {
         return id;
      }

      /**
       * @param id
       *           the id to set
       */
      public void setId( int id )
      {
         this.id = id;
      }

      /**
       * @return the is_inherited
       */
      public boolean isIs_inherited()
      {
         return is_inherited;
      }

      /**
       * @param is_inherited
       *           the is_inherited to set
       */
      public void setIs_inherited( boolean is_inherited )
      {
         this.is_inherited = is_inherited;
      }

      /**
       * @return the item_type
       */
      public String getItem_type()
      {          
         return item_type;
      }

      /**
       * @param item_type
       *           the item_type to set
       */
      public void setItem_type( String item_type )
      {
         this.item_type = item_type;
      }
   }

   public static class ModelFieldSerializer extends SimpleBeanPropertyFilter
   {
      @Override
      protected boolean include( BeanPropertyWriter writer )
      {
         return true;
      }

      @Override
      protected boolean include( PropertyWriter writer )
      {
         return true;
      }

      @Override
      public void serializeAsField( Object pPojo, JsonGenerator pJgen,
            SerializerProvider pProvider, PropertyWriter pWriter )
            throws Exception
      {
         if( pPojo instanceof FieldTemplateObject )
         {
             boolean vAllowId = ((FieldTemplateObject) pPojo).isIs_inherited();
             if( !vAllowId && ("id".equals( pWriter.getName() )) )
             {
               return; // skip the id property
             }
             else
             {
               super.serializeAsField( pPojo, pJgen, pProvider, pWriter );
             }
         }
      }
    }
}

使用条件动态排除Jackson json序列化中的POJO属性

3 个答案: