Question

我在表格中有2个列... 这是：

HCode           No_of contacts
AA1             78
AA2             10 
AA3             09
AA4             14
AA5             10 
AA1             21

我写了以下代码：

select HCode, Sum(No_of contacts) as NoOFContacts
from #T
Group by  HCode 
order by  HCode

使用上面的代码，如何根据max（[No_of contacts]）填充Percentage列？

Answer 1

也许这就是你想要的？

select 
    HCode, 
    Sum([No_of contacts]) as NoOFContacts, 
    Sum([No_of contacts])*100/(select Sum([No_of contacts]) from #t) as Percentage
from #t
Group by HCode 
order by HCode

这会产生以下结果：

HCode      NoOFContacts Percentage
---------- ------------ -----------
AA1        99           69
AA2        10           7
AA3        9            6
AA4        14           9
AA5        10           7

(5 row(s) affected)

Answer 2

您可以使用嵌套的sql语句

来实现

select Hcode, (NumberAcc/SumAcc)*100 as Percentage, Sumacc
from
(select Hcode, Sum(no_Of contacts) as SumAcc, no_OfContacts as NumberAcc
from #t
group by HCode, no_OfContacts) as T

Answer 3

您可以尝试使用以下查询：

select HCode,Sum(No_of contacts ) as NoOFContacts,(Sum(No_of contacts)*100/(Select Count(*) from #T)) as Percentage
from #T
group by HCode 
order by HCode

Answer 4

您可以使用Analytical functions获取最大合同数量，而无需单独使用子句来获取此合同：

CREATE TABLE #T (HCode VARCHAR(3), No_of_contacts INT);

INSERT #T (HCode, No_of_contacts)
VALUES ('AA1', 78), ('AA2', 10), ('AA3', 09), 
        ('AA4', 14), ('AA5', 10), ('AA1', 21);

SELECT  HCode,
        No_of_contacts,
        PercentOfContracts = 100.0 * No_of_contacts / MAX(No_of_contacts) OVER()
FROM    (   SELECT  HCode,
                    No_of_contacts = SUM(No_of_contacts)
            FROM    #T
            GROUP BY Hcode
        ) AS t;

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