如何基于远程资源的类的一部分创建新数组

Question

我在php编程方面非常新，我尝试在google上搜索此stackoverflow以获得此解决方案，但仍然没有得到它

我使用以下代码;

$url   = 'http://best1st.info/Moviedb/json.php?m=tt2015381&o=json';
$newdata = json_decode(file_get_contents($alsoKnownAs));

$alsoKnownAs = $data['ALSO_KNOWN_AS'];
echo "<pre>";
$newdata = json_decode(file_get_contents($alsoKnownAs));
echo "<pre>";
print_r($newdata);

我尝试从IMDB数据中操作Array，如果数组输出如下：

. and so on
.
.
[TOP_250] => 52
[OSCARS] => 
[AWARDS] => 
[NOMINATIONS] => 
[VOTES] => 166,773
[LANGUAGE] => Array
    (
        [0] => English
    )

[COUNTRY] => Array
    (
        [0] => USA
        [1] => UK
    )

[STORYLINE] => On planet Earth in 1988, young Peter Quill ( ) sits in the waiting room of a hospital...
[ALSO_KNOWN_AS] => Array
    (
        [0] => Guardianes de la galaxia = Argentina
        [1] => Qalaktikanin Mühafizeçileri = Azerbaijan
        [2] => Пазителите на Галактиката = Bulgaria (Bulgarian title)
        [3] => Guardiões da Galáxia = Brazil
    )

[RELEASE_DATES] => Array
    (
        [0] => USA = 21 July 2014
        [1] => UK = 24 July 2014
        [2] => Canada = 29 July 2014
        [3] => Argentina = 31 July 2014
.
.
. and so on

我如何创建一个只有＆＃34; ALSO_KNOWN_AS＆＃34;值？

谢谢你

Answer 1

简单。由于您需要的数据已保存为数组，您可以使用;

检索它

$alsoKnownAs = $newdata->ALSO_KNOWN_AS;

所以你的代码看起来像这样;

$url   = 'http://best1st.info/Moviedb/json.php?m=tt2015381&o=json';
$newdata = json_decode(file_get_contents($url));

$alsoKnownAs = $newdata->ALSO_KNOWN_AS;

然后，您可以使用以下内容循环显示值;

foreach($alsoKnownAs as $value) {
    echo '<pre>' . $value . '</pre><br>'; // to print each row of the data
    // $value is the value of each part of the array in turn, starting from 0
}