首先让我说我非常处于学习使用Angular的初级阶段。我已经完成了多次搜索，并看到了设置子菜单菜单的多个示例，但是我发现在子菜单中没有子菜单。
我也是，你可能已经注意到，也不是很擅长写一个问题。让我继续代码和一个小提琴的例子。希望有人可以解释为什么这不起作用以及我的逻辑出错了。
的JavaScript
var App = angular.module("rcfdto",[]);
App.controller("menuController", ['$scope', function($scope){
$scope.locs = [
{
name: "Menu Option #1",
link: "#OP1",
id: "Option1",
submenu: null
},
{
name: "Menu Option #2",
link: "#OP2",
id: "Option2",
submenu: [
{
name: "Submenu Option 1",
link: "#SOP1",
id: "SubOption1",
subsubmenu: null
},
{
name: "Submenu Option 2",
link: "#SOP2",
id: "SubOption2",
subsubmenu: null
},
{
name: "Submenu Option 3",
link: "#SOP3",
id: "SubmenuOption3",
subsubmenu: [
{
name: "SubSubMenu Option 1",
link: "#SSOP1",
id: "SubSubmenuOption1"
},
{
name: "SubSubMenu Option 2",
link: "#SSOP2",
id: "SubSubmenuOption2"
}
]
}
]
},
{
name: "Menu Option #3",
link: "#OP3",
id: "Option3",
submenu: [
{
name: "Submenu Option 4",
link: "#SOP4",
id: "SubmenuOption4",
subsubmenu: [
{
name: "SubSubMenu Option 3",
link: "#SSOP3",
id: "SubSubmenuOption3"
}
]
},
{
name: "Submenu Option 5",
link: "#SOP5",
id: "SubmenuOption5",
submenu: null
}
]
}
];
}]）;
HTML
<body ng-app="rcfdto">
<div class="menu container" ng-controller="menuController">
<ul class="dropdown-menu" role="menu" aria-labelledby="dLabel">
<li ng-repeat="loc in locs" ng-class="{'dropdown-submenu' : loc.submenu && loc.submenu.length}">
<a href="{{loc.link}}" id="{{loc.id}}">{{loc.name}}</a>
<ul ng-if="loc.submenu && loc.submenu.length" class="dropdown-menu">
<li ng-repeat="subloc in loc.submenu">
<a href="{{subloc.link}}" id="{{subloc.id}}">{{subloc.name}}</a>
<ul ng-if="subloc.subsubmenu && subloc.subsubmenu.length" class="dropdown-menu">
<li ng-repeat="subsubloc in subloc.subsubmenu">
<a href="{{subsubloc.link}}" id="{{subsubloc.id}}">{{subsubloc.name}}</a>
</li>
</ul>
</li>
</ul>
</li>
</ul>
CSS
.menu {
position:relative;
}
.menu > .dropdown-menu {
position:static;
display:block;
}
答案 0 :(得分：1)
您忘了在菜单上设置正确的课程。
<ul class="dropdown-menu" role="menu" aria-labelledby="dLabel">
<li ng-repeat="loc in locs" ng-class="{'dropdown-submenu' : loc.submenu && loc.submenu.length}">
<a href="{{loc.link}}" id="{{loc.id}}">{{loc.name}}</a>
<ul ng-if="loc.submenu && loc.submenu.length" class="dropdown-menu">
<!-- ng-class added in this line -->
<li ng-repeat="subloc in loc.submenu" ng-class="{'dropdown-submenu' : subloc.subsubmenu && subloc.subsubmenu.length}">
<a href="{{subloc.link}}" id="{{subloc.id}}">{{subloc.name}}</a>
<ul ng-if="subloc.subsubmenu && subloc.subsubmenu.length" class="dropdown-menu">
<li ng-repeat="subsubloc in subloc.subsubmenu">
<a href="{{subsubloc.link}}" id="{{subsubloc.id}}">{{subsubloc.name}}</a>
</li>
</ul>
</li>
</ul>
</li>
</ul>
我建议重命名＆＃34; subsubmenu＆＃34;只是＆＃34;子菜单＆＃34;并从这个混乱的结构中提取指令。