我想将我的二进制文件（在字符串中）转换为十六进制字符串，这只是一个程序片段，因为这个程序只是另一个更大程序的一部分：
//the variable name of the binary string is: "binary"
int digitNumber = 1;
int sum = 0;
int test = binary.length()%4;
if(test!=0) {
binary = padLeft(binary, test);
}
for(int i = 0; i < binary.length(); i++){
if(digitNumber == 1)
sum+=Integer.parseInt(binary.charAt(i) + "")*8;
else if(digitNumber == 2)
sum+=Integer.parseInt(binary.charAt(i) + "")*4;
else if(digitNumber == 3)
sum+=Integer.parseInt(binary.charAt(i) + "")*2;
else if(digitNumber == 4 || i < binary.length()+1){
sum+=Integer.parseInt(binary.charAt(i) + "")*1;
digitNumber = 0;
if(sum < 10)
System.out.print(sum);
else if(sum == 10)
System.out.print("A");
else if(sum == 11)
System.out.print("B");
else if(sum == 12)
System.out.print("C");
else if(sum == 13)
System.out.print("D");
else if(sum == 14)
System.out.print("E");
else if(sum == 15)
System.out.print("F");
sum=0;
}
digitNumber++;
}
public static String padLeft(String s, int n) {
return String.format("%0$"+n+"s", s);
}//i added this for padding
问题是我不知道填充是否有效，但我确信这个程序返回二进制字符串的十六进制错误转换我试图这样做：
http://www.wikihow.com/Convert-Binary-to-Hexadecimal
PS：我需要实现它（不使用任何内置函数）
答案 0 :(得分：26)
如果您不必自己实现该转换，则可以使用现有代码：
int decimal = Integer.parseInt(binaryStr,2);
String hexStr = Integer.toString(decimal,16);
如果您必须自己实施，您的代码中会出现一些问题：
sum必须重置为0. System.out.print(digitNumber); - 您应该在此处打印sum，而不是digitNumber。以下是大多数固定代码的外观：
int digitNumber = 1;
int sum = 0;
String binary = "011110101010";
for(int i = 0; i < binary.length(); i++){
if(digitNumber == 1)
sum+=Integer.parseInt(binary.charAt(i) + "")*8;
else if(digitNumber == 2)
sum+=Integer.parseInt(binary.charAt(i) + "")*4;
else if(digitNumber == 3)
sum+=Integer.parseInt(binary.charAt(i) + "")*2;
else if(digitNumber == 4 || i < binary.length()+1){
sum+=Integer.parseInt(binary.charAt(i) + "")*1;
digitNumber = 0;
if(sum < 10)
System.out.print(sum);
else if(sum == 10)
System.out.print("A");
else if(sum == 11)
System.out.print("B");
else if(sum == 12)
System.out.print("C");
else if(sum == 13)
System.out.print("D");
else if(sum == 14)
System.out.print("E");
else if(sum == 15)
System.out.print("F");
sum=0;
}
digitNumber++;
}
输出：
7AA
仅当二进制数字的数量除以4时才有效，因此您必须添加左0填充作为预备步骤。
答案 1 :(得分：3)
你可以尝试这样的事情。
private void bitsToHexConversion(String bitStream){
int byteLength = 4;
int bitStartPos = 0, bitPos = 0;
String hexString = "";
int sum = 0;
// pad '0' to make input bit stream multiple of 4
if(bitStream.length()%4 !=0){
int tempCnt = 0;
int tempBit = bitStream.length() % 4;
while(tempCnt < (byteLength - tempBit)){
bitStream = "0" + bitStream;
tempCnt++;
}
}
// Group 4 bits, and find Hex equivalent
while(bitStartPos < bitStream.length()){
while(bitPos < byteLength){
sum = (int) (sum + Integer.parseInt("" + bitStream.charAt(bitStream.length()- bitStartPos -1)) * Math.pow(2, bitPos)) ;
bitPos++;
bitStartPos++;
}
if(sum < 10)
hexString = Integer.toString(sum) + hexString;
else
hexString = (char) (sum + 55) + hexString;
bitPos = 0;
sum = 0;
}
System.out.println("Hex String > "+ hexString);
}
希望这会有所帮助：D
答案 2 :(得分：0)
import java.util.*;
public class BinaryToHexadecimal
{
public static void main()
{
Scanner sc=new Scanner(System.in);
System.out.println("enter the binary number");
double s=sc.nextDouble();
int c=0;
long s1=0;
String z="";
while(s>0)
{
s1=s1+(long)(Math.pow(2,c)*(long)(s%10));
s=(long)s/10;
c++;
}
while(s1>0)
{
long j=s1%16;
if(j==10)
{
z="A"+z;
}
else if(j==11)
{
z="B"+z;
}
else if(j==12)
{
z="C"+z;
}
else if(j==13)
{
z="D"+z;
}
else if(j==14)
{
z="E"+z;
}
else if(j==15)
{
z="F"+z;
}
else
{
z=j+z;
}
s1=s1/16;
}
System.out.println("The respective Hexadecimal number is : "+z);
}
}
答案 3 :(得分：0)
通过给定二进制数01011011，我们将它首先转换为十进制数，每个数字将Math.pow()减去长度：
01011011 =（0×2（7））+（1×2（6））+（0×2（5））+（1×2（4））+（1×2（3））+ （0×2（2））+（1×2（1））+（1×2（0））
=（0×128）+（1×64）+（0×32）+（1×16）+（1×8）+（0×4）+（1×2）+（1×1 ）
= 0 + 64 + 0 + 16 + 8 + 0 + 2 + 1
= 91（二进制数的十进制形式）
现在获得十进制数后，我们必须将其转换为十六进制数。
所以，91大于16.所以，我们必须除以16。
除以16后，商为5，余数为11。
剩余少于16。
十六进制的余数是B.
商数为5，余数的十六进制数为B.
即，91 = 16×5 + 11 = B
5 = 16×0 + 5 = 5
= <强> 5B
<强>实施
String hexValue = binaryToHex(binaryValue);
//Display result
System.out.println(hexValue);
private static String binaryToHex(String binary) {
int decimalValue = 0;
int length = binary.length() - 1;
for (int i = 0; i < binary.length(); i++) {
decimalValue += Integer.parseInt(binary.charAt(i) + "") * Math.pow(2, length);
length--;
}
return decimalToHex(decimalValue);
}
private static String decimalToHex(int decimal){
String hex = "";
while (decimal != 0){
int hexValue = decimal % 16;
hex = toHexChar(hexValue) + hex;
decimal = decimal / 16;
}
return hex;
}
private static char toHexChar(int hexValue) {
if (hexValue <= 9 && hexValue >= 0)
return (char)(hexValue + '0');
else
return (char)(hexValue - 10 + 'A');
}
答案 4 :(得分：0)
/ * *要更改此许可证标题，请在“项目属性”中选择“许可证标题”。 *要更改此模板文件，请选择工具|范本 *并在编辑器中打开模板。 * / 包字符串处理；
/ ** * * @作者Zayeed Chowdhury * / 公共类StringProcessing {
/**
* @param args the command line arguments
*/
public static void main(String[] args) {
// TODO code application logic here
int index = 0;
String bin = "0000000101100101011011100110011100000001000000000000000010101010010101100110010101100011011010010110110101100001001000000100111001100101011101000111011101101111011100100110101101110011001000000100100001000001010100110010000001001001010100110101001101010101010001010100010000100000010000010010000001010010010001010101000101010101010010010101001001000101010001000010000001010111010001010100010101001011010011000101100100100000010101000100010101010011010101000010000001000110010011110101001000100000010101000100100001000101001000000100011001001111010011000100110001001111010101110100100101001110010001110010000001000011010011110101010101001110010101000100100101000101010100110010111101000001010100100100010101000001010100110011101000100000010100000110100101101110011000010110110000101100001000000100000101011010001110110010000001000001010101000010000000000001111000000011000100110010001110100011000100110011001000000101000001001101001000000100111101001110";
String[] hexString = new String[bin.length() / 4];
for (int i = 0; i < bin.length() / 4; i++) {
hexString[i] = "";
for (int j = index; j < index + 4; j++) {
hexString[i] += bin.charAt(j);
}
index += 4;
}
for (int i = 0; i < bin.length() / 4; i++) {
System.out.print(hexString[i] + " ");
}
System.out.println("\n" + bin.length());
String[] result = binaryToHex(hexString);
for (int i = 0; i < result.length; i++) {
System.out.print("" + result[i].toUpperCase());
}
System.out.println("");
}
public static String[] binaryToHex(String[] bin) {
String[] result = new String[bin.length];
for (int i = 0; i < bin.length; i++) {
result[i] = Integer.toHexString(Integer.parseInt(bin[i], 2));
}
//return Integer.toHexString(Integer.parseInt(bin[0], 2));
return result;
}
}
答案 5 :(得分：0)
将其用于任何二进制字符串长度：
String hexString = new BigInteger(binaryString, 2).toString(16);
答案 6 :(得分：0)
private final String [] hexValues = {“ 0”，“ 1”，“ 2”，“ 3”，“ 4”，“ 5”，“ 6”，“ 7”，“ 8”，“ 9” ，“ A”，“ B”，“ C”，“ D”，“ E”，“ F”};
someCondition