Question

我从微软支持网站获得此代码它允许您从应用程序运行外部进程它在执行程序后给出输出，但我想在屏幕上发生输出我该怎么做？

using System;
using System.Diagnostics;
using System.IO;

namespace Way_Back_Downloader
{

internal class RunWget
{
    internal static string Run(string exeName, string argsLine, int timeoutSeconds)
    {
        StreamReader outputStream = StreamReader.Null;
        string output = "";
        bool success = false;

        try
        {
            Process newProcess = new Process();
            newProcess.StartInfo.FileName = exeName;
            newProcess.StartInfo.Arguments = argsLine;
            newProcess.StartInfo.UseShellExecute = false;
            newProcess.StartInfo.CreateNoWindow = true;
            newProcess.StartInfo.RedirectStandardOutput = true;
            newProcess.Start();



            if (0 == timeoutSeconds)
            {
                outputStream = newProcess.StandardOutput;
                output = outputStream.ReadToEnd();

                newProcess.WaitForExit();
            }
            else
            {
                success = newProcess.WaitForExit(timeoutSeconds * 1000);

                if (success)
                {
                    outputStream = newProcess.StandardOutput;
                    output = outputStream.ReadToEnd();
                }

                else
                {
                    output = "Timed out at " + timeoutSeconds + " seconds waiting for " + exeName + " to exit.";
                }

            }
        }
        catch (Exception exception)
        {
            throw (new Exception("An error occurred running " + exeName + ".", exception));
        }
        finally
        {
            outputStream.Close();
        }
        return "\t" + output;
    }
}
}

Answer 1

ReadToEnd显然无效 - 在流关闭之前无法返回（或者它不会读到最后）。相反，使用ReadLine编写循环。

string line;
while ((line = outputStream.ReadLine()) != null) {
   Console.WriteLine("Have line: " + line);
}

另外，将RedirectStandardOutput保留为false（默认值）将不允许捕获输出，但将在此上下文中立即显示输出

如何实现流的输出流？

1 个答案: