Question

所以这基本上就是我的主题。（这是针对C）

char score[50];

if (num == 0){
    score = "draw";
    }
else if (num == 1){ 
    score = "100";
    }
else if (num == 2){
    score = "200";
    }

但是当从类型int分配类型char [50]时，我一直收到错误，不兼容的类型。我该如何解决这个错误？

Answer 1

使用strcpy： char *strcpy(char *dest, const char *src)

#include <string.h>    //include the library containing the function strcpy

if (num == 0){
    strcpy(score, "draw");
}
else if (num == 1){ 
   strcpy(score, "100");
}
else if (num == 2){
    strcpy(score, "200");
}

Answer 2

将您的类型更改为const char *

const char* score;

if (num == 0){
    score = "draw";
}
else if (num == 1){ 
    score = "100";
}
else if (num == 2){
    score = "200";
}

Answer 3

无法将数据分配给数组...我们可以将数据分配为个体。在将字符串移动到数组中，使用strcpy函数，如下所示

  char score[50];

   if (num == 0){
   strcpy(score,"draw");
   }
   else if (num == 1){ 
   strcpy(score,"100");
   }
   else if (num == 2){
   strcpy(score,"200");
   }

无法直接复制到数组......

将字符串分配给char数组时不兼容的类型

3 个答案: