Question

嘿伙计们，我有这个ID ABCD000000001XYZL

public class SmartCounter {
 public String SmartCounter(String strID){
 intNumber =Integer.parseInt(strID.replaceAll("\\D+",""));
 intNumber += 1;
 strReturn = "ABCD"+intNumber+"XYZL";
 (strReturn);           
 }
}

我只是问我如何在Number部分中添加1并将其返回到字符串中而不会丢失零？ TIA：D

Answer 1

假设id的格式为

4个字母
9个数字
4个字母

您可以使用Regex解析它，增加数字，然后重建它。像这样：

public static void main(String[] args) throws Exception {
    final Pattern pattern = Pattern.compile("(\\D{4})(\\d{9})(\\D{4})");
    final String input = "ABCD000000001XYZL";
    final Matcher matcher = pattern.matcher(input);
    if (matcher.matches()) {
        final String head = matcher.group(1);
        final long number = Long.parseLong(matcher.group(2)) + 1;
        final String tail = matcher.group(3);
        final String result = String.format("%s%09d%s", head, number, tail);
        System.out.println(result);
    }
}

你可以使用snazzier Regex和Matcher.appendReplacement来缩短代码;以复杂性为代价：

public static void main(String[] args) throws Exception {
    final Pattern pattern = Pattern.compile("(?<=\\D{4})(\\d{9})(?=\\D{4})");
    final String input = "ABCD000000001XYZL";
    final Matcher matcher = pattern.matcher(input);
    final StringBuffer result = new StringBuffer();
    if (matcher.find()) {
        final long number = Long.parseLong(matcher.group(1)) + 1;
        matcher.appendReplacement(result, String.format("%09d", number));
    }
    matcher.appendTail(result);
    System.out.println(result);
}

Answer 2

看看DecimalFormat我相信你可以自己弄明白

Answer 3

你可以使用String.format(String, Object...)之类的东西，

class SmartCounter {
    private int id = 1;

    public SmartCounter() {
        this.id = 1;
    }

    public SmartCounter(int id) {
        this.id = id;
    }

    public String smartCounter() {
        return String.format("ABCD%09dXYZL", id++);
    }
}

您可以像

一样运行

public static void main(String[] args) {
    SmartCounter sc = new SmartCounter();
    for (int i = 0; i < 3; i++) {
        System.out.println(sc.smartCounter());
    }
}

输出

ABCD000000001XYZL
ABCD000000002XYZL
ABCD000000003XYZL

如何创建每次添加但不删除零的ID（0）

3 个答案: