Question

编辑：对于那些认为这是重复的人，它不是，因为它是没有返回任何内容的查询，而不是返回的结果。 $ id === FALSE方法不起作用!!

我遇到了代码问题（如下）。变量$ fn和$ ln是对数据库的查询，当被回显时，显示正确的输出，但是，在第二个mysql_result（mysql_query（））中它会产生错误通知我：

警告：mysql_result（）要求参数1为resource，boolean 给定的 /Applications/XAMPP/xamppfiles/htdocs/falsenine/createTeam.php上线 47

注意：查询正在尝试从正确命名的数据库，表，列名等中进行选择。

代码：

$clubID = 1;

$gkNum = rand(2,3);
$lbNum = rand(1,2);
$rbNum = rand(1,2);
$cbNum = rand(3,5);
$lmNum = rand(1,2);
$rmNum = rand(1,2);
$cmNum = rand(3,5);
$stNum = rand(2,4);

$teamNum = $gkNum + $lbNum + $rbNum + $cbNum + $lmNum + $rmNum + $cmNum + $stNum;

    while ($gkNum > 0) {
        $role = rand(1,2);
        $age = rand(16, 29);
        $nationality = rand(1, 27);         
        $nation = mysql_result(mysql_query("SELECT `nation` FROM nations WHERE `nationid` = " . $nationality), 0);
        $firstName = rand(1,20);
        $firstName = $firstName + (($nationality * 20) - 20);
        $fn = mysql_result(mysql_query("SELECT `fn` FROM firstName WHERE `nationality` = " . $nationality . " AND `fnid` = " . $firstName), 0);
        $lastName = rand(1,20);
        $lastName = $lastName + (($nationality * 20) - 20);
        $ln = mysql_result(mysql_query("SELECT `ln` FROM lastName WHERE `nationality` = " . $nationality . " AND `lnid` = " . $lastName), 0);
        mysql_query("INSERT INTO players (position, role, age, nationality, firstName, lastName, clubID) VALUES ('gk', $role, $age, '$nation', '$fn', '$ln', $clubID)");
        $id = mysql_result(mysql_query("SELECT `player_id` FROM players WHERE `firstName` = " . $fn . " AND `lastName` = " . $ln . " AND `clubID` = " . $clubID), 0);
        mysql_query("INSERT INTO playerStats (playerid) VALUES ($id)");
        $gkNum--;
    }

非常感谢任何帮助，如果需要更多详细信息，请告诉我们！谢谢！

期待资源，布尔给出问题

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