Question

我有一个名为＆＃34; list＆＃34;的文件。我需要打印出某些信息而不是整个文件。我的文件如下：

pool
pool/return
pool/home
pool/home/audits
pool/home/audits/2013
pool/home/audits/2014
pool/home/exchanges
pool/home/term
pool/transfers

我需要打印＆＃34; / home /＆＃34;除了＆＃34;审核/＆＃34;部分。这是我的代码：

#!/usr/bin/python
searchfile = open('list', 'r')
for line in iter(searchfile):
    if '/home' and not 'home/audits' in line:
            print line.strip()
searchfile.close()

我得到以下内容：

pool
pool/return
pool/home
pool/home/exchanges
pool/home/term
pool/transfers

但我需要它才能打印：

pool/home/exchanges
pool/home/term

Answer 1

你必须检查＆＃39; / home＆＃39;排队和家庭/审计＆＃39;排队：

if '/home' in line and not 'home/audits' in line:

条件if '/home' and not 'home/audits' in line:

转换为if True and not 'home/audits' in line:

因为bool('/home')（或bool('any string')）始终为True，只要填充字符串

Python：从文件中打印出某些文本

1 个答案: