Question

在我的表“团队”中，我有玩家的唯一ID（player_1，player_2，player_3，player_4，player_5），在我的表“玩家”中，这些ID是玩家的名字。例如，在搜索脚本案例中（按名称搜索）：

The user write "foo" but "foo" is ID 20.

"teams" ID 1 => player_1 ID = 20
"players" player_id = 20 > name = foo

这是我的问题：

$sql = 'SELECT * FROM teams LEFT JOIN players ON players.name LIKE :word';

但它不起作用，因为我不...

Answer 1

尝试以下查询

select * from teams as tm,players as py where tm.player_1=py.player_id and py.name LIKE 'foo%'

为什么你需要加入团队表？您只能使用玩家表格按名称搜索。

Answer 2

加入id = player_id并按名称搜索：

select * from teams join players on player_id = ID where name like 'Adam%';
+-----------+---------+----+---------+
| player_id | team_id | ID | name    |
+-----------+---------+----+---------+
|         1 |       1 |  1 | Adam G. |
|         3 |       2 |  3 | Adam S. |
+-----------+---------+----+---------+

sqlfiddle

如果在两个表中使用相同的字段名称，则可以基于列进行连接：

select * from teams join players using (player_id) where name like '%S.';
+-----------+---------+---------+
| player_id | team_id | name    |
+-----------+---------+---------+
|         3 |       2 | Adam S. |
|         5 |       1 | Jim S.  |
+-----------+---------+---------+
2 rows in set (0.01 sec)

sqlfiddle

MySQL按ID加入2个表

2 个答案: